A 100(1−α)% confidence interval for the mean μ of a normal population when the value of σ is known is given by:\[\left( \bar{x} - z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}}, \, \bar{x} + z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}} \right)\]By how much must the sample size \( n \) be increased if the width of the confidence interval above is to be halved?Halving the length requires \( n \) to be increased by a factor of [blank space].If the sample size is increased by a factor of 49, what effect will this have on the width of the interval?Increasing the sample size by a factor of 49 will [dropdown with options: --Select--, increase, decrease] the length by a factor of [blank space].Need Help? [Read It button]

Introduction: The confidence interval for the population mean, μ for a normal distribution of the…

Answered: A 100(1 – a)% confidence interval for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

Which of the following samples would have the largest standard error of the mean? It's not possible to tell n = 32 scores from a population with σ = 10 n = 89 scores from a population with σ = 20 n = 88 scores from a population with σ = 10 n =18 scores from a population with σ = 20
By how many times does the sample size have to be increased to decrease the margin of error by a facgtor of 1/9?
A random sample of n=16 scores is obtained from a population with a standard deviation of 16. If the sample mean is greater than 8 points greater than the population mean, what is the z-score for the sample mean?
A simple random sample of size n=30 is drawn from a population that is normally distributed. The sample mean is found to be 25 and the sample standard deviation is found to be 2. The claim is the population mean is different from 26 at 5% significance. Calculate the value of the test statistics? Round to 2 decimal places.
How large a sample must be taken to be 99% confident that the estimate of the average time of long-distance calls is within 5 minutes of the true average time of long-distance calls of all customers? A previous study indicated that the standard deviation for long-distance calls is 30 minutes.
If a standard deviation is 1.4 away from a mean of 7.2 what is the z score of an x value of 10
A sample of n=36 scores has a standard error of 3. What is the standard deviation of the population from which the sample is obtained?
Under which circumstance is a score that is located 5 points above the mean a central value that is relatively close to the mean? when the population mean is much less than 5 when the population mean is much greater than 5 when the population standard deviation is much less than 5 when the population standard deviation is much greater than 5
A sample of N = 9 individuals participates in a repeated measures study that produces a sample mean difference of X = 4.25 with SS = 128 for the difference scores. Is this mean difference large enough to be considered a real positive effect?
The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 79.2 for a sample of size 909 and standard deviation 20.2. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 98% confidence level). Enter your answer as a tri-linear inequality accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).
How would you figure this out? I had gotten the first two wrong.
How large a sample must be taken to be 99% confident that the estimate of the average time of long-distance calls is within 3 minutes of the true average time of long-distance calls of all customers? A previous study indicated that the standard deviation for long-distance calls is 20 minutes.

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