Biology = genetics please do Challenge problem 3 Now, figure out the complementation groups. This shows how many genes are involved in this pathway. Some of the mutant classes in the previous problem must contain more than one complementation group (gene) For example class 2 is defined by mutants 1,3,4,6, and 7. These mutants may, or may not, all be in the same gene. Complementation testing will help you know if they are, or are not, in the same gene. So there are actually additional steps between some of the letters. For example, maybe instead of XàY, it is really X->F->G->Y. CHALLENGE PROBLEM 3 The 10 mutants in ChallengeProblem 2 were tested for complementation in all pairwisecombinations using heterokaryons. The results are shownin the matrix, in which + indicates the ability of the hetero-karyon to grow in minimal medium and - indicates inabil-ity to grow in minimal medium.46 7 89.102Mutant 1 +34+78.Assume that each complementation group defines adifferent gene, and assume further that each geneencodes an enzyme that catalyzes a single step in themetabolic pathway, which converts one molecule ofsubstrate into one molecule of product.(a) Redraw the metabolic pathway deduced from Chal-lenge Problem 2. Use a right arrow to indicate eachenzymatic step in the pathway, and label each arrowwith the mutant number 1-10 that blocks the enzy-matic step. In some cases, you will not be able to specifythe order in which the enzymes occur in the pathway,so you may write them in any order you wish.(b) In the metabolic pathway that you have deduced fromthe data, how many unknown intermediates are therebetween the precursor P and the vitamin Z?9 + + ++ + + + |+ ++ + + + +LO3.+ +LO Challenge problem 2In this problem, just put the order of the intermediates on the pathway, starting with P and ending withZ and explain your reasoning. (So to get you started, notice the class 1 mutants-and there is onlymutant in this class, which is mutant #5-won't grow on minimal medium, but will grow if you give itsubstance Z. However, giving it substances, p, w, x, or y won't help. This means that the gene that ismutated lies on the pathway in a place that the Z substances is to its right and all the other substancesare to its left. The easiest next one to look at is the line with 2 pluses, and then the line with 3 pluses,and then the line with 4 pluses)P- No Class mutants growsX - Class 2 mutants ie (1,3,4,6,7) grows on this mediumw- Class 2 (1,3,4,6,7) and Class 3(2) mutants grow in this mediumY- Class 2 (1,3,4,6,7) Class 3(2) and Class 4(8,9,10) mutants grow in this mediumZ- All the Class mutants grow in this medium.-P -> X -> W -> Y ->P WYClass I (mutant 5)Class II (mutants 1, 3, 4, 6, 7)Class III (mutant 2)Class IV (mutants 8, 9, 10)Draw a linear metabolic pathway with P on the left and zon the right, in which each of the intermediates W, X, andY is shown in the order in which it occurs in the metabolicpathway in the synthesis of Z from P.区N + +

Name: Biology = genetics please do Challenge problem 3 Now, figure out the
Uploaded: 2024-03-20T06:42:55.000Z
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Description: Biology = genetics please do Challenge problem 3 Now, figure out the complementation groups. This shows how many genes are involved in this pathway. Some of the mutant classes in the previous problem must contain more than one complementation group