Cengage Learnin ✓ Cengage Learnin ✓ Cengage Learnin OWLv2 | Online ✓ b Cengage Learnin what are the unit X ChatGPT Buy iPhone 15 a ✓ prod03-cnow-owl.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator-assignment-take Ex3 CH 14 and 15 Question 1 1 pt Calculate the activation energy, Ea, for the reaction Question 2 1 pt 2 N2O5 (g) 4 NO2 (g) + O2(g) Question 3 2 pts Question 4 2 pts = k at 25 °C 3.46 × 105 s¯ from the observed rate constants: -1 and -3 k at 55 °C 1.50 × 10 = S¹. The gas constant R is 8.3145 × 103 kJ/mol · K. Question 5 1 pt Ea = kJ/mol Question 6 × 2 pts Question 7 1 pt Submit Answer Try Another Version 2 item attempts remaining Question 8 2 pts Question 9 1 pt Question 10 2 pts Question 11 1 pt Question 12 1 pt Question 13 1 pt Question 141pt Question 151pt Progress: 14/15 items Due Mar 28 at 11:45 PM Finish Assignment [References] Cengage Learning | Cengage Technical Support Previous Next Email Instructor Save and Exit

Cengage Learnin ✓ Cengage Learnin ✓ Cengage Learnin OWLv2 | Online ✓ b Cengage Learnin what are the unit X ChatGPT Buy iPhone 15 a ✓ prod03-cnow-owl.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator-assignment-take Ex3 CH 14 and 15 Question 1 1 pt Calculate the activation energy, Ea, for the reaction Question 2 1 pt 2 N2O5 (g) 4 NO2 (g) + O2(g) Question 3 2 pts Question 4 2 pts = k at 25 °C 3.46 × 105 s¯ from the observed rate constants: -1 and -3 k at 55 °C 1.50 × 10 = S¹. The gas constant R is 8.3145 × 103 kJ/mol · K. Question 5 1 pt Ea = kJ/mol Question 6 × 2 pts Question 7 1 pt Submit Answer Try Another Version 2 item attempts remaining Question 8 2 pts Question 9 1 pt Question 10 2 pts Question 11 1 pt Question 12 1 pt Question 13 1 pt Question 141pt Question 151pt Progress: 14/15 items Due Mar 28 at 11:45 PM Finish Assignment [References] Cengage Learning | Cengage Technical Support Previous Next Email Instructor Save and Exit

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The following initial rate data are for the oxidation of arsenate ion by cerium(IV) ion in aqueous solution:AsO33- + 2 Ce4+ + H2OAsO43- + 2 Ce3+ + 2 H+ Experiment [AsO33-]o, M [Ce4+]o, M Initial Rate, M s-1 1 1.26×10-2 0.541 1.90×10-3 2 2.52×10-2 0.541 3.80×10-3 3 1.26×10-2 1.08 7.57×10-3 4 2.52×10-2 1.08 1.51×10-2 Complete the rate law for this reaction in the box below.Use the form k[A]m[B]n , where '1' is understood for m or n and concentrations taken to the zero power do not appear. Don't enter 1 for m or n. Rate = From these data, the rate constant is M-2s-1.
An egg takes 10 minutes to boil under the following conditions: 100°C and 1 atm at the surface 1) Show that the rate constant for the reaction is 0.1min-1 2) Determie the activation energy and pre-exponential factor for the reaction using the Arrhenius equation. 3) You must use the expression for the rate constant from activated complex theory (transition state theory) to indicate the changes in enthalpy and entropy for the activation process.You need to consider what the changes in enthalpy and entropy mean for the reaction.
For Problem no. 23-25 Given the following data for the NH4* + NO2- N2 + 2H20 reaction Trial [NH4*) [NO2] Rate 1 0.015 M 0.020 M 0.020 M/s 2 0.030 0.020 0.040 0.015 0.010 0.005 The rate constant k is O 4444.44 M² sec O 3333.33 M2 sec-1 66.67 M-1 sec-1 O 2.22 x 105 M3 sec-1
History Bookmarks A prod01-cnow-owl.cengagenow.com X OWLV2 | Online teaching Bb Content Vacancies | A.| Birmingham New NCOER C..e Mea CAU EMAIL CANVAS Pirate Ship MYJSCC BLACKBOARD Paraphrasing .ewriting Tool Car note [References] In a series of experiments on the decomposition of dinitrogen pentoxide, N2O5, rate constants were determined at two different temperatures. At 35°C, the rate constant was 1.4 x 10- /s: at 45°C, the rate constant was 5.0 x 10-4 /s. a. What is the activation energy for this reaction? (Enter your answer to two significant figures.) ot Activation energy = J/mol pt b. What is the value of the rate constant at 65°C? pt (Enter your answer to two significant figures.) pt Rate constant = /s pt 1 pt Submit Answer Try Another Version 3 item attempts remaining 1 pt 1 pt 1 pt 1 pt 1 pt 1 pt DEC 3 10 étv MacBook Air 80 DII DD F2 F3 F4 F5 F6 F7 F8 F9 F10 23 $ & 4 7 R T Y U * CO 3.
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4. Graphing the results from kinetics experiments with enzyme inhibitors The following kinetic data were obtained for an enzyme in the absence of inhibitor (1), and in the presence of two different inhibitors (2) and (3) at 5 mM concentration. Assume [Er] is the same in each experiment. [S] (mM) 1 2 4 8 12 1 2 4 8 12 [S] (mm) a. Determine Vmax and Km for the enzyme. b. Determine the type of inhibition and the Kıfor each inhibitor. 1/[S] M-1 Plot these data as double-reciprocal Lineweaver-Burk plots and use your graph to answers a. and b. 1000 500 250 125 83.3 Answer: The data may be analyzed using double-reciprocal variables. For each [S] and corresponding u, we will calculate 1/[S] and 1/v. sed to get mo Helmien (1) v (μmol/mL sec 12 20 29 35 40 1/v (1) v (1) μmol/mL se mL-sec/umol C 12 20 29 35 40 Please explain how to get K 1/v 20 × 104 10 × 104 -400 8.33x104 5.00x104 3.45x104 2.86x104 2.50x104 Condition No inhibitor 0 5 mM inhibitor (2) 5 mM inhibitor (3) Plots of 1/v vs. 1/[S]…
For the gas phase isomerization of methyl cis-cinnamate,cis-C6H5CH=CHCOOCH3trans-C6H5CH=CHCOOCH3the rate constant has been determined at several temperatures. When ln k in s-1 is plotted against the reciprocal of the Kelvin temperature, the resulting linear plot has a slope of -2.09×104 K and a y-intercept of 24.3.The activation energy for the gas phase isomerization of methyl cis-cinnamate is kJ/mol.
Please help me determine the integrated rate law and justify the answer
Ph OTs NaSCH₂ DMF NaCN DMSO Chem 240 Lab Activity 7: Reaction Mechanisms NaOMe MeOH
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9. The following shows 3 step reaction mechanism of decomposition reaction of N₂Os: T Step 1: ka,ka. N₂O5 NO₂ + NO3 sili od bluow Jadw .sbflluzib (ka for the forward reaction a noitushogs Step 2: to fom (NO₂ + NO3 mobilusis Step 3: hilleil, NO + N₂O. N₂05→ Using steady-state approximation, deduce the decomposition rate of N₂O5. dX=TA ction and ka' for the reverse reaction) ka for the reverse reaction to g 00.211 NO₂+ O₂ + NOO Saoitoloe aid) lo imioq gailiod NO₂ + NO₂ + Nouillod to 256 bus (garA) NO₂ (q 01)
find the number of moles of acetic acid adsorbed per gram of C ?