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Can you explain the mathematical operation with the yellow balloon? Example 3.2. A generating station has a connected load of 43MW and a maximum demand of 20 MW; the units generated being 61.5 x 10° per annum. Calculate (i) the demand factor and (ii) load factor. Solution. (i) Demand factor = Max. demand 20 Connected load 43 = = 0.465 (ii) Average demand = Units generated/annum Hours in a year 61.5×106 = 7020 kW 8760 Average demand Load factor = 7020 = 0.351 or 35-1% Max. demand 20 x 10 wby

Can you explain the mathematical operation with the yellow balloon? Example 3.2. A generating station has a connected load of 43MW and a maximum demand of 20 MW; the units generated being 61.5 x 10° per annum. Calculate (i) the demand factor and (ii) load factor. Solution. (i) Demand factor = Max. demand 20 Connected load 43 = = 0.465 (ii) Average demand = Units generated/annum Hours in a year 61.5×106 = 7020 kW 8760 Average demand Load factor = 7020 = 0.351 or 35-1% Max. demand 20 x 10 wby

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can you explain the mathematical operation with the yellow balloon? Example 3.2. A generating station has a connected load of 43MW and a maximum demand of 20 MW; the units generated being 61.5 x 10° per annum. Calculate (i) the demand factor and (ii) load factor. Solution. (i) Demand factor = Max. demand 20 Connected load 43 = = 0.465 (ii) Average demand = Units generated/annum Hours in a year 61.5×106 = 7020 kW 8760 Average demand Load factor = 7020 = 0.351 or 35-1% Max. demand 20 x 10 wby
Transcribed Image Text:Can you explain the mathematical operation with the yellow balloon? Example 3.2. A generating station has a connected load of 43MW and a maximum demand of 20 MW; the units generated being 61.5 x 10° per annum. Calculate (i) the demand factor and (ii) load factor. Solution. (i) Demand factor = Max. demand 20 Connected load 43 = = 0.465 (ii) Average demand = Units generated/annum Hours in a year 61.5×106 = 7020 kW 8760 Average demand Load factor = 7020 = 0.351 or 35-1% Max. demand 20 x 10 wby
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