Calculate the standard entropy change for the following process at 298 K: H₂(g) + Br₂(g) → 2 HBr(g) 130.7 J mol K' The standard entropies are as follows: S • Include a negative sign in your answer, if appropriate. • Round your answer to the nearest tenth. Provide your answer below: SH₂ (8) JK Spr. (8) = 245.5 J mol K' SHBr(g) and So 198.7 J mol K

Calculate the standard entropy change for the following process at 298 K: H₂(g) + Br₂(g) → 2 HBr(g) 130.7 J mol K' The standard entropies are as follows: S • Include a negative sign in your answer, if appropriate. • Round your answer to the nearest tenth. Provide your answer below: SH₂ (8) JK Spr. (8) = 245.5 J mol K' SHBr(g) and So 198.7 J mol K

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A chemicai engineer is studying the two reactions shown in the table below. In each case, she fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 135.0 °C and constant total pressure. Then, she measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of her measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. ΔΗ - 1648. kJ AS = 4038. K 2Fe,0, (s) → 4Fe(s) + 30, (g) AG = ||kJ Which is spontaneous? this reaction the reverse reaction neither AH = - 803. kJ AS = K CH, (g) + 20,(g) → co,(g)…
What is the change in entropy (positive, negative, or zero) for the system? 2CO (g) + O2 (g) --> 2CO2 (g)
i need help with these pleasee Consider the reaction: 2NH3(g) +202(g) → N₂O(g) + 3H₂O(1) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.64 moles of NH3(g) react at standard conditions. ΔS Substance AH (kJ/mol) NH3(g) As O₂(g) N₂O(g) H₂O (1) surroundings Consider the reaction: system -46.1 0.0 82.1 -285.8 H₂CO(g) + O2(g) → CO₂(g) + H₂O(1) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 1.63 moles of H₂CO(g) react at standard conditions. J/K J/K Substance Sº (J/K mol) H₂CO(g) 219.0 0₂ (9) 205.1 CO₂(g) 213.7 H₂O(l) 69.9 SUVIL
Give the correct stereochemistry AND regiochemistry of the major product for the reaction shown:
Consider the following reaction: 2 H,S(g) + 30,(g) –- 2 H,O(g) + 2 SO,(g) and the following table of standard enthalpies of formation and standard absolute entropies: compound AH (kJ mol") s° (JK' mol") H,S(g) -20.6 205.8 02(g) 205.2 H2O(g) |-241.8 188.8 So,(9) |-296.8 248.2
The energy produced by a spontaneous reaction is often used to provide the energy to drive nonspontaneous reactions. For example, the conversion of ATP to ADP in our cells acts as the energy source for the nonspontaneous reactions that combine amino acids during protein synthesis. Here is the conversion of ATP to ADP: ATP(aq) + H,O = ADP(aq) + HPO,²-(aq) AG° = -30.0 kj/mol A typical reaction combining two amino acids during protein synthesis has a AG = 15.0 kJ/mol. What is the minimum ATP concentration required to provide the energy to combine 1 mole of amino acid synthesis (total energy = 15.0 kJ)? Assume that the concentration of ADP = 9 µM (micromolar) and HPO42- = 4 mM (millimolar). %3! %3D
Consider the following reaction: 2 H2(g) + 2 NO(g) N2(g) + 2 H20(g) and the following table of standard enthalpies of formation and standard absolute entropies: compound AH (kJ mol-1) s° (J K-1 mol-1) H2(g) 130.8 NO(g) 91.3 210.8 N2(g) 191.6 H20(g) -241.8 188.8
1) Predict the sign (+ or -) of the entropy for the system and justify your answer. H2 (g) + ½ O2 (g) → H2O (l) 2) Calculate the entropy change for each of the above using your data tables. H2 (g) + ½ O2 (g) → H2O (l) ΔS° =? Note: Please answer number 1 and 2 Thank you.
0/5 Nerbs A chemical engineer is studying the two reactions shown in the table below. In each case, she fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 85.0 °C and constant total pressure. Then, she measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of her measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. do AH = -2220. kJ J AS = -6189 K C,H, (g) + 50, (g) 3Co, (g) + 4H,0(1) AG = KJ Which is spontaneous? O this reaction O the reverse reaction O neither AH = -50. kJ 0- AS =…
AG (ky/mol) SUbStance / 1on so (ky/mol) -1206.9 /moi k) 92.9 • CaC03l>) -|128.8 • CaO (s) |- 635. I – 60 3.5 38.2 • CO2(9) - 393.5 - 394.4 213.7 191.5 3 H2(g) 202.7 ZNH3 ) -45.9 -16 193 • Hz (g) 202.7 223.0 -92.31 - 95. 30 186.79
A chemicai engineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 42.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. ΔΗ Ξ - 70. kJ J AS = -151. K TiCl, (g) + 2H,0(g) → Tio, (s) + 4H Cl (g) AG = || kJ Which is spontaneous? this reaction the reverse reaction neither AH = 439. kJ AS = K 4H,PO, (s) →…
Estimate the entropy change for the reaction: 2NO2 (g) + N204 (g) Standard entropy and enthalpy of formation S (U/mol K) Species H>(8) H(g) O:(8) O(g) N:(g) N(g) NO(g) H,O (g) H;0 (1) N,0 (g) NO2 (g) N2O N,Os(g) N20s(s) NHANO,(s) AH", (kJ/mol) 130.6 114.6 218.0 205 161 249.2 191.5 153.2 472.7 210.7 90.25 188.7 -241.8 69.91 -285.8 219.7 82.05 240.0 33.2 304.2 9.2 356 11 178 -43.1 151.1 -365.6