C,H12O6(s) + 6 02(g) 6 CO2(g) + 6 H,0(g) AS, +900. J/(moln · K) %3D Substance Approximate S (J/(mol - K)) C,H12O6(s) 209 O2(g) 205 H2O(g) CO2(g) 214

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Chapter1: Chemical Foundations
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C,H12O6(s) + 6 O2(g) 6 CO,(g) + 6 H20(g)
AS,
+900. J/(mol,
· K)
Substance
Approximate S (J/(mol - K))
C,H12O6(s)
209
O2(g)
205
H2O(g)
CO2(g)
214
presents the combustion of glucose, and the table provides the approximate standard absolute entropies, S, for some
used to calculate an approximation of S for H2O(g)?
- 205 – 214] J/(mol - K)
+(6 x 205) - (6 x 214)] J/(mol K)
(6 x 214) + 209 + (6 x 205)] J/(mol K)
Transcribed Image Text:C,H12O6(s) + 6 O2(g) 6 CO,(g) + 6 H20(g) AS, +900. J/(mol, · K) Substance Approximate S (J/(mol - K)) C,H12O6(s) 209 O2(g) 205 H2O(g) CO2(g) 214 presents the combustion of glucose, and the table provides the approximate standard absolute entropies, S, for some used to calculate an approximation of S for H2O(g)? - 205 – 214] J/(mol - K) +(6 x 205) - (6 x 214)] J/(mol K) (6 x 214) + 209 + (6 x 205)] J/(mol K)
« < 9of
(6)0
H,O(g)
205
?
Co2(g)
214
The chemical equation above represents the combustion of glucose, and the table provides the approximate standard absolute entropies, S, for some substances. Based on the information given,
which of these equations can be used to calculate an approximation of S for H20(g)?
S° = [900 + 209 + 205 – 214] J/(mol K
S° = 1900 + 209 + (6 x 205) - (6 x 214)] J/(mol K)
S° = - 900 - (6 x 214) + 209 + (6 x 205)] J/(mol K)
S° = [- 900 - 214 + 209 + 205] J/(mol K)
US
Transcribed Image Text:« < 9of (6)0 H,O(g) 205 ? Co2(g) 214 The chemical equation above represents the combustion of glucose, and the table provides the approximate standard absolute entropies, S, for some substances. Based on the information given, which of these equations can be used to calculate an approximation of S for H20(g)? S° = [900 + 209 + 205 – 214] J/(mol K S° = 1900 + 209 + (6 x 205) - (6 x 214)] J/(mol K) S° = - 900 - (6 x 214) + 209 + (6 x 205)] J/(mol K) S° = [- 900 - 214 + 209 + 205] J/(mol K) US
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