in ha ion hes andand reductien potental -1.25 V. An engineer proposes using this hafeaction at the cahode of a gahc o tht t080 V of eetrical powe The cell wil operate under standand andtions audents aume the engineer requires this haifreaction to hapen at the cathade of the c A Ag A () 00 Au a) L A( Au Ca ( Ce Cale Ca a 501 MacBook Air
in ha ion hes andand reductien potental -1.25 V. An engineer proposes using this hafeaction at the cahode of a gahc o tht t080 V of eetrical powe The cell wil operate under standand andtions audents aume the engineer requires this haifreaction to hapen at the cathade of the c A Ag A () 00 Au a) L A( Au Ca ( Ce Cale Ca a 501 MacBook Air
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![12:311
ull 5G
1 TikTok
A tain haif-readtion has a standard reduction potential -1.2S V. An engineer proposes using this half-reaction at the cathode of a palvanic cel that
must provide at lest 0.80 V of electrical pewer The cell will operate under standard conditions
Note for advanced shudents assume the engineer requires this half-reaction to happen at the cathode of the cell
Ag (e) - Ag )
theremium standard reduction
hat the haee
- Dv
ys there isamu
A (a)+ A ()
Aut taal+e Au ()
1.4
, check the yes box and calulate
A (a)+ e Au (s)
1.4
no minimum
ea theck
Ba aa)+ 2e Ba (s)
2.912
Bra (0+ 2e 28 (al
Calaa) + 2 Ca (s
-3.0
herea mi
o andand
Oz (a) 2 20 (
1.
s, there isamam
he anode of ths c
Co (a) + 2e" Co ()
Ca caale Ca (aa
-4.28
4.28
check the "ye bo and caloute
emamum yr an
1.82
ne maximum
(a) + 3e"C()
C ( ()
C (a) + o 0)- 3e-CO ()+ SOr (aa)
-. 44
ng the tormationin the ALS
Det wte n
-4.11
.349
Cudt(es) Cu (
Cu" (ag)+ Cu ()
Fa lab r (
fe 2 e
re c (
elt t
2.0
4.41
nion
Check
MacBook Air](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd61b6772-1f69-4fa3-8553-04a65cf6b22e%2F686a54d2-4a48-42da-a04c-32a3d00e5070%2Fybhnarq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12:311
ull 5G
1 TikTok
A tain haif-readtion has a standard reduction potential -1.2S V. An engineer proposes using this half-reaction at the cathode of a palvanic cel that
must provide at lest 0.80 V of electrical pewer The cell will operate under standard conditions
Note for advanced shudents assume the engineer requires this half-reaction to happen at the cathode of the cell
Ag (e) - Ag )
theremium standard reduction
hat the haee
- Dv
ys there isamu
A (a)+ A ()
Aut taal+e Au ()
1.4
, check the yes box and calulate
A (a)+ e Au (s)
1.4
no minimum
ea theck
Ba aa)+ 2e Ba (s)
2.912
Bra (0+ 2e 28 (al
Calaa) + 2 Ca (s
-3.0
herea mi
o andand
Oz (a) 2 20 (
1.
s, there isamam
he anode of ths c
Co (a) + 2e" Co ()
Ca caale Ca (aa
-4.28
4.28
check the "ye bo and caloute
emamum yr an
1.82
ne maximum
(a) + 3e"C()
C ( ()
C (a) + o 0)- 3e-CO ()+ SOr (aa)
-. 44
ng the tormationin the ALS
Det wte n
-4.11
.349
Cudt(es) Cu (
Cu" (ag)+ Cu ()
Fa lab r (
fe 2 e
re c (
elt t
2.0
4.41
nion
Check
MacBook Air
![kamalaa.n:1 love Tt
ll 5G
1 TikTok
2H+ (ag) + 2e-- H2 (g)
0.000
2H20 (1) + 2e" - H2 (9) + 20H" (aq)
-0.8277
H202 (aq) + 2H+ (aq) + 2e + 2H20 (1)
1.776
I2 (s) + 2e - 21 (aq)
2103- (aq) + 12H+ (aq) + 10e- + 12 (s) + 6H20 (1)
0.5355
1.195
Mg2+ (aq) + 2e +
Mg (s)
-2.372
Mn2+ (ag) + 2e" Mn (s)
-1.185
Mno, + 4H+ (aq) + 2e - Mn2+ (aq) + 2H20 (1)
1.224
Mno4 (aq) + 8H+ (aq) + 5e" - Mn2+ (aq) + 4H20 (1)
1.507
Mno4 (aq) + 2H20 (1) + 3e - MnO2 (s) + 40H (aq)
0.595
HNO2 (aq) + H* (aq) + e- NO (g) + H20 (1)
0.983
N2 (9) + 4H20 (1) + 4e" - 40H" (aq) + N2H4 (aq)
-1.16
NO3 (aq) + 4H* (aq) + 3e" - NO (9) + 2H20 (1)
0.957
Na* (aq) + e - Na (s)
-2.71
Ni2+ (aq) + 2e- Ni (s)
-0.257
02 (9) + 4H* (aq) + 4e" - 2H20 (1)
1.229
0.401
O2 (9) + 2H2O (1) + 4e - 40H (aq)
0.695
O2 (9) + 2H* (aq) + 2e - H2O2 (aq)
-0.1262
Pb2+ (aq) + 2e"- Pb (s)
-0.3588
PbSO4 (s) + H* (aq) + 2e Pb (s) + HSOA (ag)
k Air
4)
FII
F10
F9
F7
F8
delete](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd61b6772-1f69-4fa3-8553-04a65cf6b22e%2F686a54d2-4a48-42da-a04c-32a3d00e5070%2Fqw5a1gd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:kamalaa.n:1 love Tt
ll 5G
1 TikTok
2H+ (ag) + 2e-- H2 (g)
0.000
2H20 (1) + 2e" - H2 (9) + 20H" (aq)
-0.8277
H202 (aq) + 2H+ (aq) + 2e + 2H20 (1)
1.776
I2 (s) + 2e - 21 (aq)
2103- (aq) + 12H+ (aq) + 10e- + 12 (s) + 6H20 (1)
0.5355
1.195
Mg2+ (aq) + 2e +
Mg (s)
-2.372
Mn2+ (ag) + 2e" Mn (s)
-1.185
Mno, + 4H+ (aq) + 2e - Mn2+ (aq) + 2H20 (1)
1.224
Mno4 (aq) + 8H+ (aq) + 5e" - Mn2+ (aq) + 4H20 (1)
1.507
Mno4 (aq) + 2H20 (1) + 3e - MnO2 (s) + 40H (aq)
0.595
HNO2 (aq) + H* (aq) + e- NO (g) + H20 (1)
0.983
N2 (9) + 4H20 (1) + 4e" - 40H" (aq) + N2H4 (aq)
-1.16
NO3 (aq) + 4H* (aq) + 3e" - NO (9) + 2H20 (1)
0.957
Na* (aq) + e - Na (s)
-2.71
Ni2+ (aq) + 2e- Ni (s)
-0.257
02 (9) + 4H* (aq) + 4e" - 2H20 (1)
1.229
0.401
O2 (9) + 2H2O (1) + 4e - 40H (aq)
0.695
O2 (9) + 2H* (aq) + 2e - H2O2 (aq)
-0.1262
Pb2+ (aq) + 2e"- Pb (s)
-0.3588
PbSO4 (s) + H* (aq) + 2e Pb (s) + HSOA (ag)
k Air
4)
FII
F10
F9
F7
F8
delete
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