An electrochemical cell utilizes the following redox reaction NH4 + (ag) + 8Ce4*(ag) + 3H2O(I) → NO3- (ag) + 8Ce3*(ag) + 10H* (ag) Where the relevant half-reactions are: NO3 - (ag) + 10H* (ag) + 8e- → NH4 * (ag) + 3H2O Ce**(ag) + e- → Ce³*(ag) Ece = +0.88 V Ecel = +1.72 V 1. Calculate Ecu(not under standard conditions) when [NH4 1= 0.35 M, [Ce**] = 0.25 M, [NO3 -1= 5.0 x10-2 M, [Ce3+] = 6.0 ×10-2 M, and the [H*] = 1.0 x10-3 M
An electrochemical cell utilizes the following redox reaction NH4 + (ag) + 8Ce4*(ag) + 3H2O(I) → NO3- (ag) + 8Ce3*(ag) + 10H* (ag) Where the relevant half-reactions are: NO3 - (ag) + 10H* (ag) + 8e- → NH4 * (ag) + 3H2O Ce**(ag) + e- → Ce³*(ag) Ece = +0.88 V Ecel = +1.72 V 1. Calculate Ecu(not under standard conditions) when [NH4 1= 0.35 M, [Ce**] = 0.25 M, [NO3 -1= 5.0 x10-2 M, [Ce3+] = 6.0 ×10-2 M, and the [H*] = 1.0 x10-3 M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![An electrochemical cell utilizes the following redox reaction
NHa * (ag) + 8Ce4"(ag) + зн-0() > NO; (ag) + 8Ce3"(ag) + 10н* (ag)
Where the relevant half-reactions are:
NO3 - (ag) + 1OH+ (ag) + 8e- → NH4 + (ag) + 3H20
Ce**(ag) + e- > Ce3*(ag)
Ecel = +0.88 V
Ecel = +1.72 V
1. Calculate Ec(not under standard conditions) when [NH4 +1 = 0.35 M, [Ce**] = 0.25 M,
[NO3 -1= 5.0 x10-2 M, [Ce3+] = 6.0 ×10-2 M, and the [H*] = 1.0 x10-3 M
2. How is Ecel, impacted when the concentration of H* (ag) is reduced? In other words, what
happens when the pH decreases? Provide reasoning to support your answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05a8be59-6867-42ec-ad6b-7f514f5f306a%2Fe35d496f-bf60-4a9e-8380-83826b96d24d%2Fxpgkic9_processed.png&w=3840&q=75)
Transcribed Image Text:An electrochemical cell utilizes the following redox reaction
NHa * (ag) + 8Ce4"(ag) + зн-0() > NO; (ag) + 8Ce3"(ag) + 10н* (ag)
Where the relevant half-reactions are:
NO3 - (ag) + 1OH+ (ag) + 8e- → NH4 + (ag) + 3H20
Ce**(ag) + e- > Ce3*(ag)
Ecel = +0.88 V
Ecel = +1.72 V
1. Calculate Ec(not under standard conditions) when [NH4 +1 = 0.35 M, [Ce**] = 0.25 M,
[NO3 -1= 5.0 x10-2 M, [Ce3+] = 6.0 ×10-2 M, and the [H*] = 1.0 x10-3 M
2. How is Ecel, impacted when the concentration of H* (ag) is reduced? In other words, what
happens when the pH decreases? Provide reasoning to support your answer.
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