Data2H+ (aq) + 2e H2 (g)0.0002H20 (1) + 2e → H2 (g) + 20H (aq)-0.8277H202 (aq) + 2H+ (aq) + 2e 2H20 (1)1.776I2 (s) + 2e 21 (aq)0.53552103 (aq) + 12H+ (aq) + 10e → I2 (s) + 6H20 (I)1.195Mg2+ (aq) + 2e Mg (s)-2.372Mn2+ (ag) + 2e Mn (s)-1.185MnO2 (s) + 4H+ (aq) + 2e Mn2+ (aq) + 2H20 ()1.224Mn04 (aq) + 8H+ (aq) † 5e →Mn2+ (aq) + 4H20 (1)1.507MnO4 (aq) + 2H20 (1) + 3e- MnO2 (s) + 40H (aq)0.595HNO2 (aq) + H+ (aq) + e¯ → NO (g) + H2O (I)0.983N2 (g) + 4H2O (1) + 4e¯ → 4OH (aq) + N2H4 (aq)-1.16NO3 (aq) + 4H+ (aq) + 3e → NO (g) + 2H20 (1)0.957Na+ (aq) + e → Na (s)-2.71Ni2+ (aq) + 2e Ni (s)-0.25702 (g) + 4H+ (aq) + 4e¯ → 2H20 (I)1.22902 (g) + 2H2O (1) + 4e¯ → 40H (aq)0.401O2 (g) + 2H+ (aq) + 2e¯ → H202 (aq)0.695Pb2+ (aq) + 2e Pb (s)-0.1262PbSO4 (s) + H+ (aq) + 2e¯ - Pb (s) + HSO4 (aq)-0.3588CBook AirIIF8F7F9F10F1F12+9delete A certain half-reaction has a standard reduction potential Ed=-0.06 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that mustprovide at least 0.70 V of electrical power. The cell will operate under standard conditions.Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.DataAg* (aq) + e- → Ag (s)0.7996Is there a minimum standard reductionpotential that the half-reaction used atthe cathode of this cell can have?O yes, there is a minimum.EredA13+ (aq) + 3e- → Al (s)%3D-1.676Au+ (aq) + e - Au (s)1.692If so, check the "yes" box and calculatethe minimum. Round your answer to 2decimal places. If there is no lowerlimit, check the "no" box.Au3+ (aq) + 3e Au (s)1.498O no minimumBa2+ (aq) + 2e Ba (s)-2.912Br2 (1) + 2e-2Br (aq)1.066Ca2+ (aq) + 2e- - Ca (s)-2.868Is there a maximum standard reductionpotential that the half-reaction used atthe cathode of this cell can have?= IvCl2 (g) + 2e → 2C1- (aq)1.35827O yes, there is a maximum.%3DredCo2+ (aq) + 2e- → Co (s)Co3+ (aq) + e- → Co2+ (aq)Cr2+ (aq) + 2e Cr (s)-0.28If so, check the "yes" box and calculatethe maximum. Round your answer to 2decimal places. If there is no upperlimit, check the "no" box.1.92-0.913O no maximumCr3+ (ag) + 3e -Cr (s)-0.744Cr3+ (aq) + e- Cr2+ (aq)Cro42- (aq) + 4H20 (I) + 3e- + Cr(OH)3 (s) + 50H¯ (aq)Cu2+ (aq) + 2e + Cu (s)-0.407--0.13By using the information in the ALEKSData tab, write a balanced equationdescribing a half reaction that could beused at the cathode of this cell.0.3419Cu2+ (ag) + e- + Cut (aq)0.153Cu+ (aq) + e-- Cu (s)0.521Note: write the half reaction as it wouldactually occur at the cathode.2.866F2 (g) + 2eFe2+ (aq) + 2e-- Fe (s)→ 2F" (aq)-0.447Fe3+ (aq) + e- - Fe2+ (aq)Fe3+ (aq) + 3e- Fe (s)0.771ExplanationCheck-0.037MacBook AirF12F11吕0F9F10escD00 F4F7F8F6F5

Answered: Image /qna-images/answer/69beb43c-4df0-4aeb-a47a-8958d5cd3365.jpg

A certain half-reaction has a standard reduction potential Ed=-0.06 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 0.70 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell. Data Ag* (aq) + e → Ag (s) Al3+ (aq) + 3e- → Al (s) 0.7996 Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? O yes, there is a minimum. = v -1.676 Au+ (aq) + e-- Au (s) 1.692 If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Au3+ (aq) + 3e Au (s) 1.498 O no minimum Ba2+ (aq) + 2e Ba (s) -2.912 Br2 (1) + 2e- + 2Br (aq) 1.066 Ca2+ (aq) + 2e - Ca (s) -2.868 Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? E red = Iv Cl2 (g) + 2e → 2CI- (aq) 1.35827 O yes, there is a maximum. Co2+ (aq) + 2e → Co (s) -0.28 If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. Co3+ (aq) + e- → Co2+ (aq) Cr2+ (aq) + 2e - Cr (s) Cr3+ (ag) + 3e → Cr (s) 1.92 O no maximum -0.913 -0.744 Cr3+ (aq) + e- - Cr2+ (aq) --0.407 Cro42- (aq) + 4H20 (1) + 3e + Cr(OH)3 (s) + 50H- (aq) -0.13 By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Cu2+ (aq) + 2e- Cu (s) 0.3419 Cu2+ (ag) + e- + Cut (aq) 0.153 Cu+ (aq) + e-- Cu (s) 0.521 Note: write the half reaction as it would actually occur at the cathode. 2.866 F2 (g) + 2e - 2F" (aq) Fe2+ (aq) + 2e-- Fe (s) -0.447 Fe3+ (ag) + e-- Fe2+ (ag) 0.771 Explanation Check Fe3+ (ag) + 3e- Fe (s) -0.037 MacBook Air

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...