Calculate the standard enthalpy change delta Ho , for the formation of 1 mole POCl3. PCl5(g) + H2O(g) → POCl3(g ) + 2HCl(g) The information available is" 2P(white) + 3Cl2(g) + O2(g) → 2POCl3(g) - delta Ho = -1117 kJ 2HCl(g) → H2(g) + Cl2(g) - delta Ho = 184.6 kJ 3P(white) + 15/2 Cl2(g ) → 3PCl5(g) - delta Ho = -1124.7 kJ 2H2O(g ) → 2H2(g) + O2(g) - delta Ho = 483.6 kJ
Calculate the standard enthalpy change delta Ho , for the formation of 1 mole POCl3. PCl5(g) + H2O(g) → POCl3(g ) + 2HCl(g) The information available is" 2P(white) + 3Cl2(g) + O2(g) → 2POCl3(g) - delta Ho = -1117 kJ 2HCl(g) → H2(g) + Cl2(g) - delta Ho = 184.6 kJ 3P(white) + 15/2 Cl2(g ) → 3PCl5(g) - delta Ho = -1124.7 kJ 2H2O(g ) → 2H2(g) + O2(g) - delta Ho = 483.6 kJ
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Calculate the standard enthalpy change delta Ho , for the formation of 1 mole POCl3.
PCl5(g) + H2O(g) → POCl3(g ) + 2HCl(g)
The information available is"
2P(white) + 3Cl2(g) + O2(g) → 2POCl3(g) - delta Ho = -1117 kJ
2HCl(g) → H2(g) + Cl2(g) - delta Ho = 184.6 kJ
3P(white) + 15/2 Cl2(g ) → 3PCl5(g) - delta Ho = -1124.7 kJ
2H2O(g ) → 2H2(g) + O2(g) - delta Ho = 483.6 kJ
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