1. Given the thermodynamic data in the table below, calculate G° (at 298.15 K) for the reaction: 2SO2 (g) + 02 (g) 2S03 (g) Substance | AHf (kJ/mol) | S° (J/mol · K) SO2 (g) 02 (g) -297 249 205 SO3 (g) -395 256 Note: H°rx НО (prods) - H° (reacts) S°(prods) – S° (reacts) TXn TXn Go TXn H° - 2) For the equation in #1 above, calculate K, at the same (standard) conditions. G° = R = 8.314 J/mol K
1. Given the thermodynamic data in the table below, calculate G° (at 298.15 K) for the reaction: 2SO2 (g) + 02 (g) 2S03 (g) Substance | AHf (kJ/mol) | S° (J/mol · K) SO2 (g) 02 (g) -297 249 205 SO3 (g) -395 256 Note: H°rx НО (prods) - H° (reacts) S°(prods) – S° (reacts) TXn TXn Go TXn H° - 2) For the equation in #1 above, calculate K, at the same (standard) conditions. G° = R = 8.314 J/mol K
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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I only want number 2 answered. The question is based on number one

Transcribed Image Text:1. Given the thermodynamic data in the table below, calculate G° (at 298.15 K) for the reaction:
2SO2 (g) + 02 (g) 2S03 (g)
Substance | AHf (kJ/mol) | S° (J/mol · K)
SO2 (g)
02 (g)
-297
249
205
SO3 (g)
-395
256
Note: H°rx
НО (prods) -
H° (reacts)
S°(prods) – S° (reacts)
TXn
TXn
Go
TXn
H° -
2) For the equation in #1 above, calculate K, at the same (standard) conditions.
G° =
R = 8.314 J/mol K
wwww
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