Calculate the forces in members AB, BH, and BG. Members BF and CG are cables which can support tension only. Forces are positive if in tension, negative if in compression. 52 3 m Answers: AB= i BH = i H BG= i 8 KN 52 B 3 m G 11 kN c 3 m 52⁰ 52 F E kN E KN KN Ξ Ξ Ξ
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- HelpF1 F2 30 30 2. If the magnitudes F1 and F2 are both equal to 4.0 newtons, what are the horizontal and vertical components of components of the two forces? Be careful with +/- signs. Fıx = Fay =. F2x =, Fzy =.Compute the resultant of the concurrent forces shown in N. P1 = 265 N, P2= 303 N, P3 = 455 N, P4 = 192 N, 01 = 21, 02= 25, and 03= 10. Write numerical value only in 2 decimal places. P1 P4 03 8₂ + Y 0₁ P3 P2 + X
- a 1.34 kg ball is connected by means of two massless strings, each of length L = 1.70 m, to a vertical, rotating rod. The strings are tied to the rod with separation d = 1.70 m and are taut. The tension in the upper string is 35 N. What are the (a) tension in the lower string, (b) magnitude of the net force on the ball, and (c) speed of the ball? (d) What is the direction of the net force?The two masses shown in the figure are in equilibrium and the inclined plane is frictionless. m₂ m₁ 0 i If 0 = 32.0° and m₂ = 3.61 kg, determine the mass of m₁. 18.75 X kg Question 4.2c: The three masses shown in the figure are in equilibrium and the inclined plane is frictionless. If 0 = 38.4°, m₂ = 2.00 kg, and m3 = 4.86 kg, determine the mass m₁ and the magnitude of the tension 7 in the string connecting m₂ and m3. m₂ m₂ m₂ i mass m₁ = 5.02 e X kgA person pushing a uniformly-loaded 31.7 kg wheelbarrow of length L with pushing force P is attempting to get it over a step. The maximum horizontal force that the person can apply is P, = 233 N. What is the maximum height h of the step, expressed as a fraction n of the wheel's radius R. that the person can get the wheelbarrow over? The gravitational acceleration is g = 9.81 m/s². 8459 R Incorrect hnR
- Two cables BG and BH are attached to frame ACD as shown. Knowing that the tension in cable BG is 560 N, determine the components of the force exerted by cable BG on the frame at B. 1.48 m 0.56 m G m_B 0.8 m. 0.8 m 1.4 m с H D 1.2 m 1.2 m The component of the force in the x-direction is The component of the force in the y-direction is The component of the force in the z-direction is N. N. N.Three objects are connected by light strings. The string connecting the m1 = 5.65−kg object and the m2 = 4.80−kg object passes over a light frictionless pulley. A string passes over a pulley which is suspended from a horizontal surface. An object of mass m1 and an object of m2 are, respectively, attached to the left and right ends of the string as a 3.00-kg object is suspended from object m2, (a) Determine the acceleration of each object. object m1 magnitude m/s2 object m1 direction ---Select--- up down object m2 magnitude m/s2 object m2 direction ---Select--- up down object m3 magnitude m/s2 object m3 direction ---Select--- up down (b) Determine the tension in the two strings. string between m1 and m2 N string between m2 and the 3.00-kg object NThe system shown consists of 3 cables. For instance; cable C12 joins points 1 and 2. The coordinates of point 1 are (7.79, 0, 0) m, those of point 2 are (0, 7.58, 9.77) m, and those of point 3 are (0, 7.58, -9.77) m. The force P = 99 kN. Determine the force in cable C14.
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