It is not possible to see very small objects, such as viruses, using an ordinary light microscope. An electron microscope can view such objects using an electron beam instead of a light beam. Electron microscopy has proved invaluable for investigations of viruses, cell membranes and subcellular structures, bacterial surfaces, visual receptors, chloroplasts, and the contractile properties of muscles. The "lenses" of an electron microscope consist of electric and magnetic fields that control the electron beam. As an example of the manipulation of an electron beam, consider an electron traveling away from the origin along the x axis in the xy plane with initial velocity v, = vi. As it passes through the region x = 0 to x = d, the electron experiences acceleration a = a i + aj, where a and a, are constants. For the case v, = 1.91 x 10 m/s, a = 8.21 x 1014 m/s2, and a,= 1.73 x 1015 m/s?, determine the following at x = d = 0.0100 m. (a) the position of the electron Y = X m (b) the velocity of the electron v, = m/s i + m/s j (c) the speed of the electron |v,l = m/s (d) the direction of travel of the electron (i.e. the angle between its velocity and the x axis)

It is not possible to see very small objects, such as viruses, using an ordinary light microscope. An electron microscope can view such objects using an electron beam instead of a light beam. Electron microscopy has proved invaluable for investigations of viruses, cell membranes and subcellular structures, bacterial surfaces, visual receptors, chloroplasts, and the contractile properties of muscles. The "lenses" of an electron microscope consist of electric and magnetic fields that control the electron beam. As an example of the manipulation of an electron beam, consider an electron traveling away from the origin along the x axis in the xy plane with initial velocity v, = vi. As it passes through the region x = 0 to x = d, the electron experiences acceleration a = a i + aj, where a and a, are constants. For the case v, = 1.91 x 10 m/s, a = 8.21 x 1014 m/s2, and a,= 1.73 x 1015 m/s?, determine the following at x = d = 0.0100 m. (a) the position of the electron Y = X m (b) the velocity of the electron v, = m/s i + m/s j (c) the speed of the electron |v,l = m/s (d) the direction of travel of the electron (i.e. the angle between its velocity and the x axis)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A cyclotron is a machine that can be used to accelerate charged particles to achieve large kinetic energies. The resulting beams of highly energetic particles then can be used for many medical applications, including Proton Therapy (a more precise form of "radiation" used in the treatment of some cancers). A description of the cyclotron can be found in section 19.3 of the text. If a proton (of mass 1.673x10-27kg) is accelerated to its maximum velocity inside a dee with radius 1.32cm (this is the radius you would use for the "r" term in the centripetal acceleration), and if the magnetic field has a magnitude of 1.84x10-2T, what is the resulting velocity of the proton in units of km/s (kilometer per second)?
Consider the electrostatic force between two particles of equal mass m = 25.6 × 10-26 kg and carrying different charges q1 = 14e and q2 = 28e, where e denotes the magnitude of the charge on an electron. At what distance, in meters, is the electrostatic force between these two particles equal to the weight of one of them?
An electron encounters an E and B fields.B field is given by B = 0.1 j T.Electron experiences a force F = (9.6 x 10^-14 i – 9.6 x 10^-14 k)Find the electric field encountered by the electron. The velocity of the electron isv = 5 x 10^6 i m/s.
A cyclotron is used to produce a beam of high-energy deuterons that then collide with a target to produce radioactive isotopes for a medical procedure. Deuterons are nuclei of deuterium, an isotope of hydrogen, consisting of one neutron and one proton, with total mass 3.34×10−27kg. The deuterons exit the cyclotron with a kinetic energy of 6.10 MeV . What is the speed of the deuterons when they exit? If the magnetic field inside the cyclotron is 1.25 T, what is the diameter of the deuterons' largest orbit, just before they exit? If the beam current is 380 μA how many deuterons strike the target each second?
Two small metallic spheres, each of mass m = 0.204 g, are suspended as pendulums by light strings of length L as shown in the figure below. The spheres are given the same electric charge of 6.8 nC, and they come to equilibrium when each string is at an angle of 8 = 5.05° with the vertical. How long are the strings? m m L 8 m
Use the equation E=Fq E= Gravitational constant q= mass of the proton
The circular particle accelerator at CERN has a radius of about 2.24 km. The accelerator uses strong magnetic fields to steer charged particles in a circle, while electric fields give them more and more energy every time around. Suppose we're steering protons using magnetic fields of magnitude 8.22 T. What would be the magnitude of the momentum, p, of a proton under those conditions? You may assume that the magnetic field involved is perpendicular to the motion of the charges (that's the most efficient configuration).
Problem 1: In a lunapark, there is an amusement machine simply turning around with 0 = 4[t+30e−0.03 - 30] rad where t is in seconds. If the person loses consciousness at an acceleration level of 10g, a) determine the time t at which this would occur. 4 m 30 m 40 m Conductor a = 2 m/s² 3 m Figure 1 Passenger
Your object has mass 34.4 kg, and you ve separated the boxes of protons and electrons by a distance of 77 m. If you were to release the clump of protons from their box, how much acceleration would the clump of protons undergo due to its attraction to the clump of electrons in the other box? 9.56E+23 m/s^2 1.20E+23 m/s^2 2.39E+23 m/s^2 4.78E+23 m/s^2
A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass spectrometer and hits a detector at a point 10.0 cm to the left of where the beam leaves the velocity selector. The velocity selector and the detector are both in a region of magentic field of strength 0.500 T. What is the speed of the particle after it leaves the velocity selecctor? Then, what is the accelerating potential needed to reach the speed found in that part if the ions start from rest? Please also explain and show the steps you used to get there/the physics behind why/how you got to the answer to help me better understand. Thank you soo much. Also, the work and the explanation or most important because I already have the correct answer - I'm just unsure of how to get there.
A particle is launched from the origin on the ground with an initial velocityv = (2.40 m/s) x+ (2.00 m/s) y. The particle falls freely under earth’sgravitational field.a. Find the angle at which the particle is launched at origin. (angle made topositive x axis).b. How far does the particle move in the x direction?c. What is the particle’s velocity at this time?d. How long it stays in the air
Four point charges with charge +q=6.7µC are arranged in a square of side length L = 5.0 cm in the x/y plane. A fifth point charge -q=-6.7µC is placed in the center of the square but displaced a distance d=3.6 cm in the z direction. What is the net force on the negative point charge?