Answered: y Q1. If 0 = 60° and F = 20 kN,… | bartleby

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y
Q1. If 0 = 60° and F = 20 kN, determine the magnitude of the resultant force and its
direction measured clockwise from the positive x axis.
60=0
F
S
√2
50 kN
-x
Fx = 20 cos (60) = 10 kN
Fy = 20sin(60) = 17.3KN
2
FR = √(Fr) x² + (Fr) y²
FR = √(10KN)² +(17.3kN)² = 19.98 KN
29KN =
40 kN

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