0 above Consider an object sliding down a frictionless ramp that is inclined an angle the horizontal. What should the acceleration down the ramp ar be when the angle becomes zero? 0 mg

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**Physics Problem: Frictionless Ramp Motion**

**Problem Statement:**
Consider an object sliding down a frictionless ramp that is inclined at an angle θ above the horizontal. What should the acceleration down the ramp \( a_x \) be when the angle θ becomes zero?

**Diagram Explanation:**
The provided diagram shows a setup with an inclined ramp and an object placed on it. The important elements include:

- A solid block (representing the object) resting on the inclined plane.
- The angle of inclination, represented by θ.
- The force of gravity acting on the object, denoted by 'mg' directed downwards.
- A coordinate system with the x-axis parallel to the ramp and the y-axis perpendicular to the ramp.

### Analyzing the Forces

When analyzing the forces acting on the object on the inclined plane:
1. The gravitational force \( F_g = mg \) acts vertically downwards.
2. This force can be decomposed into two components:
   - Parallel to the inclined plane: \( F_{\parallel} = mg \sin(θ) \)
   - Perpendicular to the inclined plane: \( F_{\perp} = mg \cos(θ) \)

### Acceleration Calculation

Since there is no friction, the only force causing the block to accelerate down the plane is \( F_{\parallel} \).

Using Newton's Second Law along the inclined plane:
\[ F_{\parallel} = ma_x \]
\[ mg \sin(θ) = ma_x \]
\[ a_x = g \sin(θ) \]

### Special Case: θ = 0

When the angle θ becomes zero, the plane becomes horizontal. Substituting \( θ = 0 \) in the formula for acceleration:
\[ a_x = g \sin((0)) \]
\[ a_x = g \cdot 0 \]
\[ a_x = 0 \]

Therefore, the acceleration down the ramp \( a_x \) becomes zero when the angle θ is zero.
Transcribed Image Text:**Physics Problem: Frictionless Ramp Motion** **Problem Statement:** Consider an object sliding down a frictionless ramp that is inclined at an angle θ above the horizontal. What should the acceleration down the ramp \( a_x \) be when the angle θ becomes zero? **Diagram Explanation:** The provided diagram shows a setup with an inclined ramp and an object placed on it. The important elements include: - A solid block (representing the object) resting on the inclined plane. - The angle of inclination, represented by θ. - The force of gravity acting on the object, denoted by 'mg' directed downwards. - A coordinate system with the x-axis parallel to the ramp and the y-axis perpendicular to the ramp. ### Analyzing the Forces When analyzing the forces acting on the object on the inclined plane: 1. The gravitational force \( F_g = mg \) acts vertically downwards. 2. This force can be decomposed into two components: - Parallel to the inclined plane: \( F_{\parallel} = mg \sin(θ) \) - Perpendicular to the inclined plane: \( F_{\perp} = mg \cos(θ) \) ### Acceleration Calculation Since there is no friction, the only force causing the block to accelerate down the plane is \( F_{\parallel} \). Using Newton's Second Law along the inclined plane: \[ F_{\parallel} = ma_x \] \[ mg \sin(θ) = ma_x \] \[ a_x = g \sin(θ) \] ### Special Case: θ = 0 When the angle θ becomes zero, the plane becomes horizontal. Substituting \( θ = 0 \) in the formula for acceleration: \[ a_x = g \sin((0)) \] \[ a_x = g \cdot 0 \] \[ a_x = 0 \] Therefore, the acceleration down the ramp \( a_x \) becomes zero when the angle θ is zero.
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