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While an elevator of mass 812 kg moves downward, the tension in the supporting cable is a constant 7730 N. Betweent=D0 and t= 4.00 s, the elevator's displacement is 5.00 m downward. What is the elevator's speed at t= 4.00 s? m/s k nt

While an elevator of mass 812 kg moves downward, the tension in the supporting cable is a constant 7730 N. Betweent=D0 and t= 4.00 s, the elevator's displacement is 5.00 m downward. What is the elevator's speed at t= 4.00 s? m/s k nt

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The problem on the screen involves calculating the speed of an elevator. ### Problem Statement: While an elevator of mass 812 kg moves downward, the tension in the supporting cable is a constant 7730 N. Between \( t = 0 \) and \( t = 4.00 \, \text{s} \), the elevator's displacement is \( 5.00 \, \text{m} \) downward. What is the elevator's speed at \( t = 4.00 \, \text{s} \)? ### Explanation: The problem requires using the principles of physics, specifically Newton's second law and kinematic equations, to find the final speed. Variables given: - Mass of the elevator: \( 812 \, \text{kg} \) - Tension in cable: \( 7730 \, \text{N} \) - Time interval: \( 4.00 \, \text{s} \) - Displacement: \( 5.00 \, \text{m} \) downward Target: - Find the speed of the elevator at \( t = 4.00 \, \text{s} \). There are no visible graphs or diagrams that require explanation.
Transcribed Image Text:The problem on the screen involves calculating the speed of an elevator. ### Problem Statement: While an elevator of mass 812 kg moves downward, the tension in the supporting cable is a constant 7730 N. Between \( t = 0 \) and \( t = 4.00 \, \text{s} \), the elevator's displacement is \( 5.00 \, \text{m} \) downward. What is the elevator's speed at \( t = 4.00 \, \text{s} \)? ### Explanation: The problem requires using the principles of physics, specifically Newton's second law and kinematic equations, to find the final speed. Variables given: - Mass of the elevator: \( 812 \, \text{kg} \) - Tension in cable: \( 7730 \, \text{N} \) - Time interval: \( 4.00 \, \text{s} \) - Displacement: \( 5.00 \, \text{m} \) downward Target: - Find the speed of the elevator at \( t = 4.00 \, \text{s} \). There are no visible graphs or diagrams that require explanation.
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