Calculate the bar force members IJ, ID, LK and BC using method of section. ANS: IJ = 4.6 KN (C) ID = 2.24 kN (C) LK =6 KN (C) BC= 5.25 kN (T) 1 kN |--21 m 2 KN B 2 kN K -2 m 2.5 KN 2 KN £2m-f2m + E -2 m 2 kN H F 1 kN 2 m H 6 m
Calculate the bar force members IJ, ID, LK and BC using method of section. ANS: IJ = 4.6 KN (C) ID = 2.24 kN (C) LK =6 KN (C) BC= 5.25 kN (T) 1 kN |--21 m 2 KN B 2 kN K -2 m 2.5 KN 2 KN £2m-f2m + E -2 m 2 kN H F 1 kN 2 m H 6 m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![Calculate the bar force members IJ, ID,
LK and BC using method of section.
ANS: IJ = 4.6 KN (C)
ID = 2.24 KN (C)
LK =6 KN (C)
BC= 5.25 kN (T)
1 kN
|--2 m
2 KN
B
2 kN
K
2.5 KN
-2 m-+-2 m-
D
2 KN
E
-2 m2 m-
2 kN
H
2 m
1 kN
4)
G
6 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc454ce3f-cf87-47c3-943e-bf9c80a1dede%2F68ed263d-14b9-4975-a048-056a7110deb0%2Fpofcphd_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the bar force members IJ, ID,
LK and BC using method of section.
ANS: IJ = 4.6 KN (C)
ID = 2.24 KN (C)
LK =6 KN (C)
BC= 5.25 kN (T)
1 kN
|--2 m
2 KN
B
2 kN
K
2.5 KN
-2 m-+-2 m-
D
2 KN
E
-2 m2 m-
2 kN
H
2 m
1 kN
4)
G
6 m
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