5m 5m 3m B2 B4 B4 B1 3m B1 B3 B 3m B4 Superimposed D.L = 2.0 KPa Live load = 5.0 KPa B4 B1 3m (2) The floor framing plan shown carries superimposed deadload and live load. B1 B3 1. Draw the load diagram of Gridline 1 for dead load. 2. Draw the load diagram of Gridline 1 using load combination μ = 1.2 D.L. + 1.6 L.L. 3m B4 B4 B1 B1 3m B3 B1: 300mm x 600mm B2: 250mm x 600mm B3: 300mm x 500mm B4: 200mm x 400mm Slab Thickness: 150 mm
5m 5m 3m B2 B4 B4 B1 3m B1 B3 B 3m B4 Superimposed D.L = 2.0 KPa Live load = 5.0 KPa B4 B1 3m (2) The floor framing plan shown carries superimposed deadload and live load. B1 B3 1. Draw the load diagram of Gridline 1 for dead load. 2. Draw the load diagram of Gridline 1 using load combination μ = 1.2 D.L. + 1.6 L.L. 3m B4 B4 B1 B1 3m B3 B1: 300mm x 600mm B2: 250mm x 600mm B3: 300mm x 500mm B4: 200mm x 400mm Slab Thickness: 150 mm
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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STRUCTURAL THEORY 1

Transcribed Image Text:5m
5m
3m
B2
B4
B4
B1
3m
B1
B3
B
3m
B4
Superimposed D.L = 2.0 KPa
Live load = 5.0 KPa
B4
B1
3m
(2)
The floor framing plan shown carries superimposed deadload
and live load.
B1
B3
1. Draw the load diagram of Gridline 1 for dead load.
2.
Draw the load diagram of Gridline 1 using load
combination μ = 1.2 D.L. + 1.6 L.L.
3m
B4
B4
B1
B1
3m
B3
B1: 300mm x 600mm
B2: 250mm x 600mm
B3: 300mm x 500mm
B4: 200mm x 400mm
Slab Thickness: 150 mm
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Explain the process of how you solve it? thankyou
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why does it seem like only 1 way slab was made, shouldn't it be for 2 way slab solution?
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it should be using the triangle in BEAM 1 and trapezoidal in BEAM 4?
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