Use the area method. The two beams shown are connected by an internal hinge at C and are supported by a fixed support at A and a roller at D.P = 252 NW1 = 212 N/mW2 = 322 N/mM = 409 N • m terial hasUse tOWe University does nothe following tables as template for your solution.pyright of RepubShear CalculationundeopyrighRelation of Shear to Concentrated and Distributed Loadcopyright protinfringement and theVB - VA =Bending Moment CalculationRelation of Bending Moment to Applied Moment and ShearDiagramMB - MA =Shear Values (N)VA =VB =MA =MB(N)of Requblic Act A) 2930 "Intellectual Property Code of the Philippinder R8283. Any reprodua and/or ommnication of the mat you by Or2mW₁The is not your oyentdo not use it many ywere yourhof Universown.Propesohe PhilippinesProperty Coop as if iton of the material by yousuch infgement.reproduced and commulic Act (RA) 8293 or thehorize you to reproduce or commtenis makal. The Material8293. Any reproduction and/or comers have the right to ke legal acUNCAY This not your own property sany was as if itdo not use itwere four owW₂P2mMPOU5m

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you by c Feet The is not your ow of Universt W₁ do not use it any were your on Philippines Property Co as if it Proper P oduced and commun Act (RA) 8293 or the 2 unication of the material by you such ingement. horize you to reproduce or commate ois maal. The Material 8293. Any reproduction and/or co mers have the right to ke legal ac 2m P This not your own property do not use it any war as if it were four ow W₂ 2m 5m M

you by c Feet The is not your ow of Universt W₁ do not use it any were your on Philippines Property Co as if it Proper P oduced and commun Act (RA) 8293 or the 2 unication of the material by you such ingement. horize you to reproduce or commate ois maal. The Material 8293. Any reproduction and/or co mers have the right to ke legal ac 2m P This not your own property do not use it any war as if it were four ow W₂ 2m 5m M

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

The simply supported beam consists of a W21 x 44 structural steel wide-flange shape [E = 29,000 ksi; I = 843 in.“1. Assume that the support at D can provide resistance either up or down. For a loading of w = 7.2 kips/ft, determine: (a) the beam deflection Va at point A. (b) the beam deflection vc at point C. Assume LAB = 11 ft, Lec = 6 ft, LcD = 6 ft, LDE = 5 ft. В D E LAB LBC LCD LDE Answers: (a) VA = 0.9 in. (b) vc = 0.5| in.
Determine the force in each member of the loaded truss. All triangles are equilateral with side length d. The forces are positive if in tension, negative if in compression. Answers: AB= AG = BC= BG= CD= i i i i i B G 2.8 KN C d F 5.7 KN kN Ξ Ξ Ξ Ξ Ξ kN kN kN kN E
1. An angular section 120mm x 120mm x 10mm is riveted by a 22mm diameter rivets arranged as shown. Assume A36 steel with F, = 250MPA, F, = 400MPA. Diameter of hole is 3mm bigger. 60mm 40mm 120mm | 10mm 60mm >T 40mm 10mm 60mm 60mm 60mm 60mm a. Determine the capacity of the section based on yielding of gross area. b. Determine the capacity of the section based on tensile fracture of the net area. c. Determine the capacity of the section based on block shear failure.
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Replace the three forces shown by an equivalent force-couple system at point A. If the forces are replaced by a single resultant force, determine the distance d below point A to its line of action. Answers: R= i M = i 230 N d= 295 N Force-couple system at A. The force is positive if to the right, and the couple is positive if counterclockwise. Single resultant force. i 240 N 410 mm 410 mm 410 mm N N•m mm
Use AREA MOMENT METHOD to Determine the following: A central beam BD is joined at hinges to two cantilever beams AB and DE. All beams have the cross-section shown. For the loading shown, determine the largest w so that the deflection at C does not exceed 3mm. Use E=200 GPa. w 12 mm A C D E Hinge' Hinge 24 mm 0.4 m 0.4 m 0.4 m 0.4 m
The cantilever beam consists of a rectangular structural steel tube shape [E = 29,000 ksi; I = 1620 in.4]. For the loading shown, determine: (a) the beam deflection at point A. (b) the beam deflection at point B. Assume MA = 190 kip-ft, P = 26 kips, LAB = 3.6 ft, LBC = 5.4 ft. %3D %3D P V. MA C LAB LBC Answer: (a) VA = in. (b) VB = in.
Solve the problem by the moment-area method. The beam has constant flexural rigidity EI. A simple beam AB supports two concentrated loads P at the positions shown in the figure. P d B C 800 L 4 4 4 4 Ⓡ A support C at the midpoint of the beam is positioned at distance d below the beam before the loads are applied. Assuming that d = 12 mm, L = 5.4 m, E = 200 GPa, and I = 193 x 106 mm4, calculate the magnitude of the loads P (in kN) so that the beam just touches the support at C. KN L
A simply supported beam (E = 12 GPa) carries a uniformly distributed load q = 120 N/m, and a point load P = 126 N at mid-span. A |C L/2- -L/2 - The beam has a rectangular cross section (b = 75 mm, h = 200 mm) and a length of 3.6 m. Calculate the maximum deflection (in mm) of the beam. (Enter the magnitude. Solve the problem by the method of superposition. All beams have constant flexural rigidity EI.) mm
X Your answer is incorrect. The simply supported beam consists of a W21 x 44 structural steel wide-flange shape [E = 29,000 ksi; I = 843 in.“]. Assume that the support at D can provide resistance %3D either up or down. For a loading of w = 5.4 kips/ft, determine: (a) the beam deflection vg at point A. (b) the beam deflection vc at point C. Assume LAB = 13 ft, LBc = 7 ft, LcD =7 ft, LDE = 6 ft. %3D A B E LAB LBC LcD LCD Lpe Answers: (a) VA = -0.65669 in. (b) vc = 0.024937 in.