Q2. Replace the loading acting on the beam with a single resultant force. Determine (a) the force magnitude, F. (b) the horizontal angle of the force, 0. (c) how far the force should be placed from point A on the beam, x. A 60° |--2 -2 m 450 N 4 m 300 N B -3 m 700 N 30° 3000 N·m

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A: From the above diagram F1 = 12×3×3⇒F1 = 4.5 KNF2 = 6×3⇒F2 = 18 KNF3 = 12×3×3⇒F3 = 4.5 KN

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