1. For the beam and loading shown and knowing that the distributed load w can be expressed as a function of x, w=kx2, determine: a) The value of k so that the distributed load at point A is 400 lb/ft and at point B is 100 lb/ft. (Hint: x axis along beam ACB with the origin at C) b) The magnitude and location of the resultant of the distributed load using the integration approach. d) The reactions at the beam supports. 400 lb/ft A 12 ft Parabola -6 ft- 100 lb/ft B

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Please solve a) b) nd d) 

1.
For the beam and loading shown and knowing that the distributed load w can
be expressed as a function of x, w=kx², determine:
a) The value of k so that the distributed load at point A is 400 lb/ft and at point B is 100
lb/ft. (Hint: x axis along beam ACB with the origin at C)
b) The magnitude and location of the resultant of the distributed load using the integration
approach.
d) The reactions at the beam supports.
400 lb/ft
A
Parabola
in A4
B
12 ft
-6 ft-
100 lb/ft
Transcribed Image Text:1. For the beam and loading shown and knowing that the distributed load w can be expressed as a function of x, w=kx², determine: a) The value of k so that the distributed load at point A is 400 lb/ft and at point B is 100 lb/ft. (Hint: x axis along beam ACB with the origin at C) b) The magnitude and location of the resultant of the distributed load using the integration approach. d) The reactions at the beam supports. 400 lb/ft A Parabola in A4 B 12 ft -6 ft- 100 lb/ft
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