c→B 0₂ a≤ b, c =√√b(L+ a) 0₁ Wac² 2LEI L+b L+a Wab L Wac³ 3LEI 88 (at position c) (under load)
c→B 0₂ a≤ b, c =√√b(L+ a) 0₁ Wac² 2LEI L+b L+a Wab L Wac³ 3LEI 88 (at position c) (under load)
Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter8: Engineering Materials
Section: Chapter Questions
Problem 85CQ
Related questions
Question
100%
Please by using this formula
Thanks..
![A
K-c→B
·b-
a≤ b, c =√√b(L+a)
03
0₁
-
Wac²
2LEI
L+b
L+a
Wab
L
Wac³
3LEI
(at position c) (under load)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd76452ca-c5fb-4662-89d5-3a7ee477f102%2Fd9f8b3be-b554-40a7-9a6c-40ce41ea10cf%2Fm1hmy175_processed.png&w=3840&q=75)
Transcribed Image Text:A
K-c→B
·b-
a≤ b, c =√√b(L+a)
03
0₁
-
Wac²
2LEI
L+b
L+a
Wab
L
Wac³
3LEI
(at position c) (under load)
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