roblem 1 Problem 2 Derive the shear and moment equations for ach beam segment. Derive the shear and moment equ. each beam segment. 4 kN/m 2 kN/m w = 200x N/m A |B - 2 m 3 m 2 m 3 m - Answer: Answer:
roblem 1 Problem 2 Derive the shear and moment equations for ach beam segment. Derive the shear and moment equ. each beam segment. 4 kN/m 2 kN/m w = 200x N/m A |B - 2 m 3 m 2 m 3 m - Answer: Answer:
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![Problem 1
Problem 2
Derive the shear and moment equations for
each beam segment.
Derive the shear and moment equations for
each beam segment.
4 kN/m
2 kN/m
w = 200x N/m
A|
|B
- 2 m
3 m
2 m
3 m
Answer:
Answer:
VAB = -2x kN
MAB = -x? kN-m
VBC = -x?/3 – 2x/3 – 4/3 kN
MBC = -x³/9 – -x²/3 – 4x/3 + 8/9 kN-m
VAB = 540 N
МАВ 3D 540х N-m
Vвс %3D 940 — 100х? N
MBC = -100x/3 + 940x – 1600/3 N-m
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ea5f966-c26e-4577-8205-bfe7ff276c2a%2F2b273df5-4bb9-4dce-809b-cf6640482855%2Fmqkydyw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 1
Problem 2
Derive the shear and moment equations for
each beam segment.
Derive the shear and moment equations for
each beam segment.
4 kN/m
2 kN/m
w = 200x N/m
A|
|B
- 2 m
3 m
2 m
3 m
Answer:
Answer:
VAB = -2x kN
MAB = -x? kN-m
VBC = -x?/3 – 2x/3 – 4/3 kN
MBC = -x³/9 – -x²/3 – 4x/3 + 8/9 kN-m
VAB = 540 N
МАВ 3D 540х N-m
Vвс %3D 940 — 100х? N
MBC = -100x/3 + 940x – 1600/3 N-m
%3D
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