Calculate AH for the synthesis of diborane (B2H6) from its elements, according to the equation: 2B(s) + 3 Hz(g) - B2H6(g) using the following data: AH(1) AH(2) AH(3) - 1273 k); - 2035 k): %3D 3/2 02(8) (1) 2B(s) + (2) B2H6(g) + 3 02(g) + % 02lg) B203(s) B203(s) * 3H208) H2Og) 242 k) (3) H2(g)

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Chapter1: Chemical Foundations
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Calculate AH for the synthesis of diborane (B2H6) from its elements, according to the equation:
2B(s) + 3 H2(g) - B2H6(g)
using the following data:
3/2 02(8)
(1) 2B(s) +
(2) B2H6(g) + 3 0O2(g)
(3) H2(g) + ½O2(g)
B203(s)
B203(s) + 3H20(g)
H2O(g)
AH(1)
AH(2)
AH(3)
- 1273 k):
2035 k);
%3D
242 k)
%3D
45 kJ
O 33 kJ
O 45 kJ
O 33 kJ
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Transcribed Image Text:Calculate AH for the synthesis of diborane (B2H6) from its elements, according to the equation: 2B(s) + 3 H2(g) - B2H6(g) using the following data: 3/2 02(8) (1) 2B(s) + (2) B2H6(g) + 3 0O2(g) (3) H2(g) + ½O2(g) B203(s) B203(s) + 3H20(g) H2O(g) AH(1) AH(2) AH(3) - 1273 k): 2035 k); %3D 242 k) %3D 45 kJ O 33 kJ O 45 kJ O 33 kJ Click Save and Submit to save and submit. Click Save All Answers to save all answers.
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