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Macmillan Learning A 78.0 mL portion of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by adding 119 mL of water. What is the final concentration? Assume the volumes are additive. concentration: M

Macmillan Learning A 78.0 mL portion of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by adding 119 mL of water. What is the final concentration? Assume the volumes are additive. concentration: M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Foundations BIOMATH REVIE X cmillanlearning.com/courses/ac3d481b-26e6-469a-8108-28e47d641df6/5/mm6m8u/tools/assessment/items/bcc6592... A to Assignment Score: Question 11 of 14 > HT concentration: 81.2% My Course - General Chemist X Resources Give Up? Hint A 78.0 mL portion of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by adding 119 mL of water. What is the final concentration? Assume the volumes are additive. Jon Notice Ion Notice Check Answer Ⓒ M
Transcribed Image Text:Foundations BIOMATH REVIE X cmillanlearning.com/courses/ac3d481b-26e6-469a-8108-28e47d641df6/5/mm6m8u/tools/assessment/items/bcc6592... A to Assignment Score: Question 11 of 14 > HT concentration: 81.2% My Course - General Chemist X Resources Give Up? Hint A 78.0 mL portion of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by adding 119 mL of water. What is the final concentration? Assume the volumes are additive. Jon Notice Ion Notice Check Answer Ⓒ M
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Molarity is a measure of concentration which is defined as number of moles of solute present in 1l of solution.

According to law of dilution,  M1V1 = M2V2

where M and V is Molarity and Volume respectively. 

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