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c. The following molecule will undergo E2 elimination even though it looks very similar to the cyclohexane derivative above. Predict the product of the reaction and explain the difference in E2 reactivities (why does it occur on the molecule below and not on the cyclohexane derivative?) Me Me Me OTS Me ''Et NAOMe

c. The following molecule will undergo E2 elimination even though it looks very similar to the cyclohexane derivative above. Predict the product of the reaction and explain the difference in E2 reactivities (why does it occur on the molecule below and not on the cyclohexane derivative?) Me Me Me OTS Me ''Et NAOMe

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Need help with part c.  The cyclohexane derivative shown below does not undergo E2 elimination. what do we do after we roate the bond roate the bond.

Me Me Me Me Me OTS OTS Me ''Et "Et a. Complete the chair representation of the substrate. You must show all groups (including hydrogen atoms) to receive credit. b. Using your chair representation above, explain why E2 elimination does not occur. c. The following molecule will undergo E2 elimination even though it looks very similar to the cyclohexane derivative above. Predict the product of the reaction and explain the difference in E2 reactivities (why does it occur on the molecule below and not on the cyclohexane derivative?) E2 conditions no reaction NaOMe OTS
Transcribed Image Text:Me Me Me Me Me OTS OTS Me ''Et "Et a. Complete the chair representation of the substrate. You must show all groups (including hydrogen atoms) to receive credit. b. Using your chair representation above, explain why E2 elimination does not occur. c. The following molecule will undergo E2 elimination even though it looks very similar to the cyclohexane derivative above. Predict the product of the reaction and explain the difference in E2 reactivities (why does it occur on the molecule below and not on the cyclohexane derivative?) E2 conditions no reaction NaOMe OTS
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