Second base of codon U C A UUU UCU Phenylalanine UCC UAU UGU U Tyrosine tyr y Cysteine U UUC phe F Serine UAC UGC cys C UUA UCA UGA STOP codon UAA STOP codon UAG Leucine ser A UGG Tryptonphan trp W UUG leu UCG L CUU CCU CAU CGU Histidine CUC ССС САС his H CGC Arginine arg R Leucine Proline CỦA leu L ССА pro P САА Glutamine CGA CUG CG CAG gin o CGG AUU ACU AAU AGU Serine ser s Asparagine Isoleucine ACC Threonine AUC AAC asn N AGC ile | AUA ACA thr T AAA AGA Lysine Methionine AUG met (start codon ACG Arginine arg R AAG lys AGG K. GGU GUU GCU GAU Aspartic acid GAC U GUC GCC Alanine asp D GGC C Glycine gly G Valine GUA val V GCA ala A GAA Glutamic acid GGA A GUG GCG GAG glu E GGG G 8) The bolded "A" nucleotide near the beginning of line 2 is the adenine in the intron that is responsible for forming the lariat during splicing. It is thus part of the consensus splicing motif. A) If this is mutated to G, what are the 5 ribonucleotides following exon 1 in the mature MRNA transcript? 5'- -3' B) Does this mutation result in a frame shift? C) How many amino acids are in the protein encoded by the mRNA following this mutation? amino acids D) Using a codon chart (posted under the Translation module in Moodle), translate the mRNA transcript with the mutation described in 8A into protein, using the single letter amino acid code and no spaces. N terminus- -C terminus Third base of codon O

Human Anatomy & Physiology (11th Edition)
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Chapter1: The Human Body: An Orientation
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Use the first picture and codon table to answer the following questions.

Second base of codon
U
C
A
UUU
UCU
Phenylalanine
UCC
UAU
UGU
U
Tyrosine
tyr y
Cysteine
U UUC
phe F
Serine
UAC
UGC
cys C
UUA
UCA
UGA STOP codon
UAA
STOP codon
UAG
Leucine
ser
A
UGG Tryptonphan
trp W
UUG
leu
UCG
L
CUU
CCU
CAU
CGU
Histidine
CUC
ССС
САС
his
H
CGC
Arginine
arg R
Leucine
Proline
CỦA
leu L
ССА
pro P
САА
Glutamine
CGA
CUG
CG
CAG
gin o
CGG
AUU
ACU
AAU
AGU
Serine
ser s
Asparagine
Isoleucine
ACC Threonine
AUC
AAC
asn N
AGC
ile |
AUA
ACA
thr T
AAA
AGA
Lysine
Methionine
AUG met (start codon ACG
Arginine
arg R
AAG
lys
AGG
K.
GGU
GUU
GCU
GAU
Aspartic acid
GAC
U
GUC
GCC
Alanine
asp D
GGC
C
Glycine
gly G
Valine
GUA
val V
GCA
ala
A
GAA
Glutamic acid
GGA
A
GUG
GCG
GAG
glu E
GGG
G
8) The bolded "A" nucleotide near the beginning of line 2 is the adenine in the intron that is responsible
for forming the lariat during splicing. It is thus part of the consensus splicing motif.
A) If this is mutated to G, what are the 5 ribonucleotides following exon 1 in the mature MRNA
transcript?
5'-
-3'
B) Does this mutation result in a frame shift?
C) How many amino acids are in the protein encoded by the mRNA following this mutation?
amino acids
D) Using a codon chart (posted under the Translation module in Moodle), translate the mRNA
transcript with the mutation described in 8A into protein, using the single letter amino acid code and
no spaces.
N terminus-
-C terminus
Third base of codon
O <G
First base of codon
Transcribed Image Text:Second base of codon U C A UUU UCU Phenylalanine UCC UAU UGU U Tyrosine tyr y Cysteine U UUC phe F Serine UAC UGC cys C UUA UCA UGA STOP codon UAA STOP codon UAG Leucine ser A UGG Tryptonphan trp W UUG leu UCG L CUU CCU CAU CGU Histidine CUC ССС САС his H CGC Arginine arg R Leucine Proline CỦA leu L ССА pro P САА Glutamine CGA CUG CG CAG gin o CGG AUU ACU AAU AGU Serine ser s Asparagine Isoleucine ACC Threonine AUC AAC asn N AGC ile | AUA ACA thr T AAA AGA Lysine Methionine AUG met (start codon ACG Arginine arg R AAG lys AGG K. GGU GUU GCU GAU Aspartic acid GAC U GUC GCC Alanine asp D GGC C Glycine gly G Valine GUA val V GCA ala A GAA Glutamic acid GGA A GUG GCG GAG glu E GGG G 8) The bolded "A" nucleotide near the beginning of line 2 is the adenine in the intron that is responsible for forming the lariat during splicing. It is thus part of the consensus splicing motif. A) If this is mutated to G, what are the 5 ribonucleotides following exon 1 in the mature MRNA transcript? 5'- -3' B) Does this mutation result in a frame shift? C) How many amino acids are in the protein encoded by the mRNA following this mutation? amino acids D) Using a codon chart (posted under the Translation module in Moodle), translate the mRNA transcript with the mutation described in 8A into protein, using the single letter amino acid code and no spaces. N terminus- -C terminus Third base of codon O <G First base of codon
A. Below is a small 2 exon long gene. The exons are underlined, and the 22 nucleotide long intron is the non-
underlined sequence between the exons. TAG, TAA, and TGA are stop codons.
5'-TAGTGTATTGACATGATAGAAGCACTCACTATATTCTGACGTGCGACTATGCGTGGGGTTAGGT
ATTGTGCTGACTTTTCTCAGGTGGCCCGTATAGGCTAAGCTGCGCATCGCCGCTAGTCGCTCAGTTCCGC
TGGCGGCATTTTAACTTTCTTTAATGAATGCGGGCATATTTAATACGCGCTATGCGCATCGTATGCGAT-3'
Transcribed Image Text:A. Below is a small 2 exon long gene. The exons are underlined, and the 22 nucleotide long intron is the non- underlined sequence between the exons. TAG, TAA, and TGA are stop codons. 5'-TAGTGTATTGACATGATAGAAGCACTCACTATATTCTGACGTGCGACTATGCGTGGGGTTAGGT ATTGTGCTGACTTTTCTCAGGTGGCCCGTATAGGCTAAGCTGCGCATCGCCGCTAGTCGCTCAGTTCCGC TGGCGGCATTTTAACTTTCTTTAATGAATGCGGGCATATTTAATACGCGCTATGCGCATCGTATGCGAT-3'
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