For production of penicillin (C16H18O4N2S) using Penicillium mold, glucose (C6H12O6) is used as a substrate and phenylacetic acid (C3H3O2) is added as a precursor. The stoichiometry for overall synthesis is: 1.67 C6H1206 + 2NH3 + 0.502+ H2SO4+ C8H3O2 → C16H1804N2S + 2CO2+ 9H2O a) What is the maximum theoretical yield of penicillin from glucose in g/g? b) When results from a particular penicillin fermentation were analyzed, it was found that 24% of the glucose had been used for growth, 70% for cell maintenance activities (such as membrane transport and macromolecule turnover) and only 6% for penicillin synthesis. Calculate the yield of penicillin from glucose in g/g under these conditions. c) Batch fermentation under the conditions described in part b) is carried out in a 100-liter tank. Remember that only 6% of the glucose is used for penicillin synthesis. Initially, the tank is filled with nutrient medium containing 50 g L' glucose and 4 g L phenylacetic acid. If the reaction is stopped when the glucose concentration is 5.5 g L1, determine (i) Which is the limiting substrate if NH3, O2, and H2SO4 are provided in excess? (ii) The extent of reaction in mol E (iii) The total mass of glucose (in grams) used for growth (iv) The amount of penicillin (in grams) produced (v) The final concentration of phenylacetic acid in g/L

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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For production of penicillin (C16H18O4N2S) using Penicillium mold, glucose (C6H12O6) is used as a substrate and
phenylacetic acid (C3H3O2) is added as a precursor. The stoichiometry for overall synthesis is:
1.67 C6H1206 + 2NH3 + 0.502+ H2SO4+ C8H3O2 → C16H1804N2S + 2CO2+ 9H2O
a) What is the maximum theoretical yield of penicillin from glucose in g/g?
b) When results from a particular penicillin fermentation were analyzed, it was found that 24% of the glucose
had been used for growth, 70% for cell maintenance activities (such as membrane transport and
macromolecule turnover) and only 6% for penicillin synthesis. Calculate the yield of penicillin from
glucose in g/g under these conditions.
c) Batch fermentation under the conditions described in part b) is carried out in a 100-liter tank. Remember
that only 6% of the glucose is used for penicillin synthesis. Initially, the tank is filled with nutrient medium
containing 50 g L' glucose and 4 g L phenylacetic acid. If the reaction is stopped when the glucose
concentration is 5.5 g L1, determine
(i) Which is the limiting substrate if NH3, O2, and H2SO4 are provided in excess?
(ii) The extent of reaction in mol E
(iii) The total mass of glucose (in grams) used for growth
(iv) The amount of penicillin (in grams) produced
(v) The final concentration of phenylacetic acid in g/L

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(problem 2.25 textbook, see page 41) Stoichiometry and Incomplete Reactions

For production of penicillin (C₁₆H₁₈O₄N₂S) using Penicillium mold, glucose (C₆H₁₂O₆) is used as a substrate and phenylacetic acid (C₈H₈O₂) is added as a precursor. The stoichiometry for overall synthesis is:

1.67 C₆H₁₂O₆+ 2NH₃ + 0.5O₂+ H₂SO₄+ C₈H₈O₂àC₁₆H₁₈O₄N₂S + 2CO₂+ 9H₂O

What is the maximum theoretical yield of penicillin from glucose in g/g?
When results from a particular penicillin fermentation were analyzed, it was found that 24% of the glucose had been used for growth, 70% for cell maintenance activities (such as membrane transport and macromolecule turnover) and only 6% for penicillin synthesis. Calculate the yield of penicillin from glucose in g/g under these conditions.
Batch fermentation under the conditions described in part b) is carried out in a 100-liter Remember that only 6% of the glucose is used for penicillin synthesis. Initially, the tank is filled with nutrient medium containing 50 g L^-1 glucose and 4 g L^-1 phenylacetic acid. If the reaction is stopped when the glucose concentration is 5.5 g L^-1, determine: