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b If it took 24 s for the concentration to drop 65 percent from its initial value of 0.50 rate constant for the reaction? Rate constant =|0.045 L/(mol - s)

b If it took 24 s for the concentration to drop 65 percent from its initial value of 0.50 rate constant for the reaction? Rate constant =|0.045 L/(mol - s)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help sloving for problem B. I am using the second law equation and can't seem to get it right. It is not a X10^(#) answer. They want it as a L/(mol*s)

a A plot of 1/[A] versus time for the hypothetical reaction А — В +С yields a straight line. What is the order of the reaction? first-order second-order O third-order O fourth-order b If it took 24 s for the concentration to drop 65 percent from its initial value of 0.5( rate constant for the reaction? Rate constant = |0.045 L/(mol · s) An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer.
Transcribed Image Text:a A plot of 1/[A] versus time for the hypothetical reaction А — В +С yields a straight line. What is the order of the reaction? first-order second-order O third-order O fourth-order b If it took 24 s for the concentration to drop 65 percent from its initial value of 0.5( rate constant for the reaction? Rate constant = |0.045 L/(mol · s) An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer.
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