Please help A-C SubmitRequest AnswerPart C25.0 mL of a 7.00 M HCl solutionExpress your answer with the appropriate units.HA?ValueUnitsMass =SubmitRequest AnswerProvide FeedbackMacBook ProDIIDDF6F7F8F9F10F11F12&9.тYUHJKN* 00く○

Part A Volume of NaOH solution = 3.00L Molarity of NaOH solution = 4.00M Determine the moles of NaOH. Molarity = NaOH molesVolume of solution in L4.00M=NaOH moles3.00LNaOH moles=4.00M×3.00L=4.00mol/L×3.00L=12 molConvert the above moles to mass as shown below, Moles = NaOH massNaOH molar mass12 mol=NaOH mass39.997 g/molNaOH mass=12 mol×39.997 g/mol=480 g Part B Volume of KCl solution = 4.00L Molarity of KCl solution = 0.200M Determine the moles of KCl. Molarity = KCl molesVolume of solution in L0.200M=KCl moles4.00LKC moles=0.200M×4.00L=0.200mol/L×3.00L=0.6 mol Convert the above moles to mass as shown below, Moles = KCl massKCl molar mass0.6 mol=KCl mass74.5513 g/molKCl mass=0.6 mol×74.5513 g/mol=44.7 gPart C Volume of HCl solution = 25.0mL Molarity of HCl solution = 7.00M Determine the moles of HCl. Molarity = HCl molesVolume of solution in L7.00M=HCl moles25.0mL7.00M=HCl moles25.0×10-3LHCl moles=7.00M×25.0×10-3L=7.00mol/L×25.0×10-3L=0.175 mol Convert the above moles to mass as shown below, Moles = HCl massKCl molar mass0.175 mol=HCl mass36.458 g/molHCl mass=0.175 mol×36.458 g/mol=6.38 g