Axial loads are applied with rigid bearing plates to the solid cylindrical rods shown. The normal stress in aluminum rod (1) must be limited to 20 ksi, the normal stress in brass rod (2) must be limited to 24 ksi, and the normal stress in steel rod (3) must be limited to 12 ksi. Determine the minimum diameter required for each of the three rods. Assume P = 8 kips, Q = 5 kips, R = 20 kips and S = 28 kips. Calculate F1, F2, F3and.. Calculate the minimum required cross-sectional areas, and in turn, the minimum rod diameters using the rod internal forcemagnitudes and the allowable stresses for each rod material.Answers:The normal stress in aluminum rod (1) must be limited to 20 ksi; therefore, the minimum cross-sectional area required for rod (1)in² and the minimum rod diameter is therefore iisin.The normal stress in brass rod (2) must be limited to 24 ksi; therefore, the minimum cross-sectional area required for rod (2) isin² and the minimum rod diameter is therefore iin.The normal stress in steel rod (3) must be limited to 12 ksi; therefore, the minimum cross-sectional area required for rod (3) isin² and the minimum rod diameter is thereforein. etR(1) Vo(2)A(3)BSCD

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Axial loads are applied with rigid bearing plates to the solid cylindrical rods shown. The normal stress in aluminum rod (1) must be limited to 20 ksi, the normal stress in brass rod (2) must be limited to 24 ksi, and the normal stress in steel rod (3) must be limited to 12 ksi. Determine the minimum diameter required for each of the three rods. Assume P = 8 kips, Q = 5 kips, R = 20 kips and S = 28 kips.

Calculate F1, F2, F3

and..

Calculate the minimum required cross-sectional areas, and in turn, the minimum rod diameters using the rod internal force
magnitudes and the allowable stresses for each rod material.
Answers:
The normal stress in aluminum rod (1) must be limited to 20 ksi; therefore, the minimum cross-sectional area required for rod (1)
in² and the minimum rod diameter is therefore i
is
in.
The normal stress in brass rod (2) must be limited to 24 ksi; therefore, the minimum cross-sectional area required for rod (2) is
in² and the minimum rod diameter is therefore i
in.
The normal stress in steel rod (3) must be limited to 12 ksi; therefore, the minimum cross-sectional area required for rod (3) is
in² and the minimum rod diameter is therefore
in.

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