A voltaic cell operating under standard conditions (1.0 M ion concentrations) utilizes the following reaction: 3 Pb(s) + 2 Co3+(aq)  3 Pb2+(aq) + 2 Co(s)   What is the effect on the cell emf of each of the following changes: a)  A solution of 1.0 M Pb(NO3)2 is added to the anode compartment. __The positive cell emf rises, becoming more positive. __The positive cell emf drops closer to zero.     __The negative cell emf rises closer to zero. __The negative cell emf drops, becoming more negative. __No change in cell emf occurs. b)Some Na2S is added to the Pb2+ compartment, precipitating some Pb2+ as lead sulfide. ___The positive cell emf rises, becoming more positive. ___The positive cell emf drops closer to zero.     ___The negative cell emf rises closer to zero. ___The negative cell emf drops, becoming more negative. ___No change in cell emf occurs.

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A: The solution is as follows:

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