Hydrogen bromide dissociates into its gaseous elements, H₂ and Br2, at elevated temperatures. HBr(g) H₂(g) Br₂(g) AH, kJ/mol S°, J/(mol.K) -36.44 0 30.91 198.6 130.6 245.3 a. Calculate the percent dissociation at 373°C and 1.00 atm. (Enter your answer to three significant figures.) Percent dissociation = % b. What would be the percent dissociation at 373°C and 10.0 atm? (Enter your answer to three significant figures.) Percent dissociation = % c. Use data above and any reasonable approximation to obtain K. (Enter your answer to three significant figures.) K =
Hydrogen bromide dissociates into its gaseous elements, H₂ and Br2, at elevated temperatures. HBr(g) H₂(g) Br₂(g) AH, kJ/mol S°, J/(mol.K) -36.44 0 30.91 198.6 130.6 245.3 a. Calculate the percent dissociation at 373°C and 1.00 atm. (Enter your answer to three significant figures.) Percent dissociation = % b. What would be the percent dissociation at 373°C and 10.0 atm? (Enter your answer to three significant figures.) Percent dissociation = % c. Use data above and any reasonable approximation to obtain K. (Enter your answer to three significant figures.) K =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Hydrogen bromide dissociates into its gaseous elements,
H₂ and
Br2, at elevated temperatures.
HBr(g)
H₂(g)
Br₂(g)
AH, kJ/mol S°, J/(mol.K)
-36.44
0
30.91
198.6
130.6
245.3
a. Calculate the percent dissociation at 373°C and 1.00
atm.
(Enter your answer to three significant figures.)
Percent dissociation =
%
b. What would be the percent dissociation at 373°C and
10.0 atm?
(Enter your answer to three significant figures.)
Percent dissociation =
%
c. Use data above and any reasonable approximation to
obtain K.
(Enter your answer to three significant figures.)
K =
![What is the cell potential of the following voltaic cell at 25°C?
Zn(s)|
Zn²+(1.72×10¯5M)||Cu²+(0.122M) | Cu(s)
The standard cell potential of this cell is 1.10 V.
Ecell =
]
V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffcaf0374-1550-4ffb-84ad-720668c0d5ec%2Fa0b197c3-ac9b-4174-b99b-8a86f2502f74%2Ftse2dhe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What is the cell potential of the following voltaic cell at 25°C?
Zn(s)|
Zn²+(1.72×10¯5M)||Cu²+(0.122M) | Cu(s)
The standard cell potential of this cell is 1.10 V.
Ecell =
]
V
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