A voltaic cell consists of a Pb/Pb²+ half-cell and a Cu/Cu²+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu²+ are 0.0520 mol L¯1 and 1.60 mol L1, respectively. Part B What is the cell potential when the concentration of Cu²+ has fallen to 0.200 mol L-1? РЬ?+ (аq) + 2 е РЬ(s) Cu²+(aq) +2 e → Cu(s) E° = -0.13 V E° = 0.34 V Express your answer using two decimal places. ? Ecell = Value Units Submit Previous Answers Request Answer

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A voltaic cell consists of a Pb/Pb²+ half-cell and a
Cu/Cu²+ half-cell at 25 °C. The initial concentrations
of Pb2+ and Cu²+ are 0.0520 mol L and 1.60
mol L1, respectively.
Part B
What is the cell potential when the concentration of Cu2+ has fallen to 0.200 mol L-1?
РЬ2+ (aq) + 2 е РЫ (s)
Cu?+(aq) + 2 e → Cu(s)
E° = -0.13 V
E° = 0.34 V
Express your answer using two decimal places.
µA
Ecell =
Value
Units
Submit
Previous Answers Request Answer
X Incorrect; Try Again
Transcribed Image Text:A voltaic cell consists of a Pb/Pb²+ half-cell and a Cu/Cu²+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu²+ are 0.0520 mol L and 1.60 mol L1, respectively. Part B What is the cell potential when the concentration of Cu2+ has fallen to 0.200 mol L-1? РЬ2+ (aq) + 2 е РЫ (s) Cu?+(aq) + 2 e → Cu(s) E° = -0.13 V E° = 0.34 V Express your answer using two decimal places. µA Ecell = Value Units Submit Previous Answers Request Answer X Incorrect; Try Again
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