Experiment Torque : By means of diagram, show and explain how the two (2) conditions of equilibrium are applied on Procedure #4 setup. to the same external forces that act on the object.The algebraic sign of a torque is perfectly arbitrary. For convenience, clockwisetorques are usually called positive and counterclockwise torques negative.50 Gm100 CmProcedures:1. Set-up the apparatus and locate the center of gravity of the meter stick by adjustingthe point of suspension until the meter stick is in equilibrium. Record this position asthe center of gravity of the meter stick.1Ocmcle2. At the 10 cm mark of the meter stick, hang a 40 g mass. If using a holder or hanger,be sure to include its mass to the given load. Locate the position at which an 80 g behung to produce rotational equilibrium.40gB0g3. After equilibrium has been attained, convert the masses into force equivalents and thelever arms into meter. Record all torque producing forces and their respective leverarms (moment arms). Identify each torque as clockwise or counterclockwise.10Lm4. Attach two weights on thhe meter stick: at 10 cm mark, hang a 20 g mass and at 20 cmmark, 10 g mass. Balance their moments by a 60 g mass hung on the other side of thefulcrum. Repeat procedure 3 and compute the percentage deviation.10g5. Slide the point of suspension of the meter stick as far as possible toward the zero endof the meter stick. Record this position as the axis of rotation. With a loop of threadand a spring balance, apply a force near the 100 cm end of the meter stick so thatequilibrium is produced. Record the force exerted by the spring balance and themoment arm. From the law of moments, calculate the weight of the meter stick.Then weigh the meter stick on the triple beam balance and record the relativedeviation between the values.CED Cm||

Given: in procedure 4 setup:- distace of the 10 g mass from the start point on the meter stick=10cm…

arms (moment arms). Identify each torque as clockwise or counterclockwise. 10 Um 4. Attach two weights on the meter stick: at 10 cm mark, hang a 20 g mass and at 20 cm mark, 10 g mass. Balance their moments by a 60 g mass hung on the other side of the fulcrum. Repeat procedure 3 and compute the percentage deviation. 10g 209 GOg 5. Slide the point of suspension of the meter stick as far as possible toward the zero end

arms (moment arms). Identify each torque as clockwise or counterclockwise. 10 Um 4. Attach two weights on the meter stick: at 10 cm mark, hang a 20 g mass and at 20 cm mark, 10 g mass. Balance their moments by a 60 g mass hung on the other side of the fulcrum. Repeat procedure 3 and compute the percentage deviation. 10g 209 GOg 5. Slide the point of suspension of the meter stick as far as possible toward the zero end

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Chemical and Phase Equilibrium

Phase diagrams or equilibrium phase diagrams are the graphical representations that show the phase transformations of the constituting elements with respect to the pressure, temperature, and compositions. The diagrams show the conditions that limit the different phases, namely solid, liquid, and gas. The diagram can also be utilized to verify the relations between the state variables. Most of the phase diagrams are temperature-pressure phase diagrams, with the variable parameter as the composition. Usually other variables such as solubility and pressure parameters are not indicated in the phase diagram. For a one-component system (unary phase diagram), the phase diagram is generally a function of temperature and pressure as the state variables, or temperature and volume. However, for a binary system (two-phase) having two components, the phase diagram is a function of temperature and composition as the state variables only. Coexisting of the different phases of the constituting elements is indicated in the phase diagram. A ternary phase diagram can be characterized by consisting of three phases in equilibrium.

Question

Experiment Torque : By means of diagram, show and explain how the two (2) conditions of equilibrium are applied on Procedure #4 setup.

to the same external forces that act on the object.
The algebraic sign of a torque is perfectly arbitrary. For convenience, clockwise
torques are usually called positive and counterclockwise torques negative.
50 Gm
100 Cm
Procedures:
1. Set-up the apparatus and locate the center of gravity of the meter stick by adjusting
the point of suspension until the meter stick is in equilibrium. Record this position as
the center of gravity of the meter stick.
1Ocm
cle
2. At the 10 cm mark of the meter stick, hang a 40 g mass. If using a holder or hanger,
be sure to include its mass to the given load. Locate the position at which an 80 g be
hung to produce rotational equilibrium.
40g
B0g
3. After equilibrium has been attained, convert the masses into force equivalents and the
lever arms into meter. Record all torque producing forces and their respective lever
arms (moment arms). Identify each torque as clockwise or counterclockwise.
10Lm
4. Attach two weights on thhe meter stick: at 10 cm mark, hang a 20 g mass and at 20 cm
mark, 10 g mass. Balance their moments by a 60 g mass hung on the other side of the
fulcrum. Repeat procedure 3 and compute the percentage deviation.
10g
5. Slide the point of suspension of the meter stick as far as possible toward the zero end
of the meter stick. Record this position as the axis of rotation. With a loop of thread
and a spring balance, apply a force near the 100 cm end of the meter stick so that
equilibrium is produced. Record the force exerted by the spring balance and the
moment arm. From the law of moments, calculate the weight of the meter stick.
Then weigh the meter stick on the triple beam balance and record the relative
deviation between the values.
CE
D Cm
||

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