P=222.5 N **Text Transcription:**Determine the forces acting on the ground and the torque, \( T_{12} \), to maintain static equilibrium for the four-bar linkage shown in Figure using both graphical and analytical methods.\(\vec{R}_{A,O} = 87.5 \, \text{mm}, \, \vec{R}_{B,A} = \vec{R}_{B,O_2} = 150 \, \text{mm}, \, \vec{R}_{C,O} = 100 \, \text{mm}, \, \vec{R}_{D,O} = 175 \, \text{mm}, \, \text{and} \, \vec{R}_{O_4,O_2} = 175 \, \text{mm}.\)**Diagram Explanation:**The diagram depicts a four-bar linkage system. The system includes the following key components:1. **Points:** - Point A, B, C, D, O₂, O₄ are labeled to indicate specific locations on the linkage system. 2. **Bars:** - Four bars are labeled 1 through 4, which form the linkage.3. **Forces and Directions:** - An arrow labeled \( P \) is shown acting horizontally to the right at point D. - The torque \( T_{12} \) is indicated at joint O₂ with an arrow in a clockwise direction.4. **Angles:** - An angle of 105.1° is noted between lines extending from points A to O₂ and B to A. - Another angle, 152.4°, is between the horizontal line from point O₂ to O₄ and a line from O₂ to B. - A circle with an angle of 240° is inscribed around point O₂.5. **Structural Supports:** - The diagram shows fixed pivot points at O₂ and O₄, indicated by hardware symbols on horizontal lines. This figure is used to determine the static forces required for maintaining equilibrium in this particular four-bar mechanism, using given lengths and angles associated with the linkage configuration.

Determine the forces acting on the ground and the torque, T₁2, to maintain static equilibrium for the four-bar linkage shown in Figure using both graphical and analytical methods. R₁0,=87.5mm, R₂4=R30₁=150mm, co. 100 mm, Rp.175 mm, and Ro.o.=175 mm, De B 3 P 4 105.1° 240° A 2 T12 -152.4° 04

Determine the forces acting on the ground and the torque, T₁2, to maintain static equilibrium for the four-bar linkage shown in Figure using both graphical and analytical methods. R₁0,=87.5mm, R₂4=R30₁=150mm, co. 100 mm, Rp.175 mm, and Ro.o.=175 mm, De B 3 P 4 105.1° 240° A 2 T12 -152.4° 04

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

) Determine the following: X of the shaded area shown in the Figure below. The weight W of the shaded area (plate), if the plate has a thickness of 5 mm and the density of the material of the plate is 7800 kg/m³ 139 mm 30⁰ 240 mm 139 mm 139 mm R-50 mm R-45 mm 25 mm X 25 mm
Q2: Find the min. spacing of steel bolts required to make the section of beam below works a unity. If you know that diameter of bolts 10 mm and it's allowable shear stress is 14 MPa. 26 kN/m 4 m. 4 m. Steel bolts 300 200
Determine Force work done 722J Displacement = Rom.
please solve the question
A loading condition is shown below. Using Castigliano's theorem and by applying a fictitious force Q with a magnitude of 0 at point C, determine: a) The horizontal displacement of point C. a) The vertical displacement of point C.
1.73 What is the answer? Use a given-required-solution format. Provide a step by step solution with a free body diagram. Provide a handwritten solution without the use of calculator. Simplify the answer and use a proper unit.
I need the answer as soon as possible
5
Consider a project which involves the investment of P100,000 now and P100,000 at the end of one year. Revenues of P150,000 will be generated at the end of years 1 and 2. What is the present value of this project if the effective annual interest rate is 10% ? a P65,421.50 P68,421.50 b P67,421.5 d P69,421.50
I need the answer as soon as possible
13)The Beam in figure below is weightless. A moveable weight(mass)W of 300 Ibm is to be attached as shown. 420 Ibf 640 bf 3.0 ft 6.0 ft 6.0 ft A B a) Draw the FBD and show all the forces. b) Calculate force for weight(mass) W. gl= 32.174 ft/s? c) Determine summation of forces in Y direction and X direction and set=0 (EF,=0, EF,=0) d) Determine summation of moments respect to point A and set =0 (EMA=0) e) from above equations, determine the location x of the weight so that the vertical reactions at A and B are equal.
Determine the largest weight of the picture frame that can be by the two ropes Tas shown in the figure. The stress in the rope are not to exceed 1 MPa and the cross sectional area of the rope is 4.0 mm² . assume 0= 30° ... A 2 N B) 4 N C 6.9 N D) 3.5 N