13)The Beam in figure below is weightless. A moveable weight(mass)W of 300 lbm is to be attached as shown. 420 ibf 640 lbf -3.0 ft 6.0 ft 6.0ft B a) Draw the FBD and show all the forces. b) Calculate force for weight(mass) W. gl= 32.174 ft/s? c) Determine summation of forces in Y direction and X direction and set-0 (EF,=0, EF,=0)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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13)The Beam in figure below is weightless. A moveable weight(mass)W of 300 Ibm is to be
attached as shown.
420 Ibf
640 bf
3.0 ft
6.0 ft
6.0 ft
A
B
a) Draw the FBD and show all the forces.
b) Calculate force for weight(mass) W.
gl= 32.174 ft/s?
c) Determine summation of forces in Y direction and X direction and set=0 (EF,=0, EF,=0)
d) Determine summation of moments respect to point A and set =0 (EMA=0)
e) from above equations, determine the location x of the weight so that the vertical reactions at
A and B are equal.
Transcribed Image Text:13)The Beam in figure below is weightless. A moveable weight(mass)W of 300 Ibm is to be attached as shown. 420 Ibf 640 bf 3.0 ft 6.0 ft 6.0 ft A B a) Draw the FBD and show all the forces. b) Calculate force for weight(mass) W. gl= 32.174 ft/s? c) Determine summation of forces in Y direction and X direction and set=0 (EF,=0, EF,=0) d) Determine summation of moments respect to point A and set =0 (EMA=0) e) from above equations, determine the location x of the weight so that the vertical reactions at A and B are equal.
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