hree forces act on particle A located at the origin of an x-y coordinate system. Force B acts at 140o from the positive x-axis, and force C acts at 15o from the positive x-axis. The weight acts down with a magnitude of W = 100 kN. Use the equations of equilibrium to determine the magnitudes of B and C such that particle A is in equilibrium. Carefully draw a neat, labeled, free body diagram of particle C. Based on your FBD develop two equilibrium equations in terms of the symbols defined on your free body diagram. Find angles α and β. FB= 117.92 kn Fc= 93.507 K
hree forces act on particle A located at the origin of an x-y coordinate system. Force B acts at 140o from the positive x-axis, and force C acts at 15o from the positive x-axis. The weight acts down with a magnitude of W = 100 kN. Use the equations of equilibrium to determine the magnitudes of B and C such that particle A is in equilibrium. Carefully draw a neat, labeled, free body diagram of particle C. Based on your FBD develop two equilibrium equations in terms of the symbols defined on your free body diagram. Find angles α and β. FB= 117.92 kn Fc= 93.507 K
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Three forces act on particle A located at the origin of an x-y coordinate system. Force B acts at 140o from the positive x-axis, and force C acts at 15o from the positive x-axis. The weight acts down with a magnitude of W = 100 kN. Use the equations of equilibrium to determine the magnitudes of B and C such that particle A is in equilibrium. Carefully draw a neat, labeled, free body diagram of particle C. Based on your FBD develop two equilibrium equations in terms of the symbols defined on your free body diagram. Find angles α and β. FB= 117.92 kn Fc= 93.507 Kn
![### Equilibrium of a Particle
**Principles:**
For a particle to be in equilibrium, the sum of the forces acting on it must be zero. This requires that the sum of the forces in the x-direction (ΣFx) and the sum of the forces in the y-direction (ΣFy) are both equal to zero.
1. **ΣFx = 0**
2. **ΣFy = 0**
**Given Data:**
- Height \( h \) = 2.5 ft
- Distance \( d_1 \) = 4.75 ft
- Distance \( d_2 \) = 3 ft
- Load \( W \) = 50 lb
**Problem Statement:**
Determine the numeric force values with three significant figures for the system shown in the diagram. The load \( W \) is 50 lb.
**Diagram Analysis:**
The diagram depicts a particle C, which is in equilibrium under the action of:
- A horizontal member connected at points A and B.
- Two slanted members forming angles \( \alpha \) and \( \beta \) with the horizontal member.
- A vertical load \( W \) hanging from point C.
- \( A \) and \( B \) are points where the horizontal member is supported.
- \( h \) is the vertical distance from the horizontal member to the point C.
- \( d_1 \) is the horizontal distance from point A to C.
- \( d_2 \) is the horizontal distance from point C to B.
### Detailed Description of Diagram:
1. **Horizontal Member (AB):**
- Positioned horizontally with a total length \( d_1 + d_2 \).
- Ends labeled A and B.
2. **Vertical Distance (h):**
- Shown as a vertical line from the horizontal member down to C.
3. **Angles (\( \alpha \) and \( \beta \)):**
- \( \alpha \) is the angle between the horizontal member and the left slanted member.
- \( \beta \) is the angle between the horizontal member and the right slanted member.
4. **Vertical Load (W):**
- Shown as a weight hanging from point C downward.
### Equilibrium Conditions:
To solve for the forces, express the equilibrium conditions along the x and y axes, considering the geometry and dimensions provided.
\[
\Sigma F_x =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff12ec146-5781-453b-8388-2e7cc9921f6c%2F4e26cb9c-f6e2-4cd0-bc26-e0830f78d8df%2Fmqu8l9p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Equilibrium of a Particle
**Principles:**
For a particle to be in equilibrium, the sum of the forces acting on it must be zero. This requires that the sum of the forces in the x-direction (ΣFx) and the sum of the forces in the y-direction (ΣFy) are both equal to zero.
1. **ΣFx = 0**
2. **ΣFy = 0**
**Given Data:**
- Height \( h \) = 2.5 ft
- Distance \( d_1 \) = 4.75 ft
- Distance \( d_2 \) = 3 ft
- Load \( W \) = 50 lb
**Problem Statement:**
Determine the numeric force values with three significant figures for the system shown in the diagram. The load \( W \) is 50 lb.
**Diagram Analysis:**
The diagram depicts a particle C, which is in equilibrium under the action of:
- A horizontal member connected at points A and B.
- Two slanted members forming angles \( \alpha \) and \( \beta \) with the horizontal member.
- A vertical load \( W \) hanging from point C.
- \( A \) and \( B \) are points where the horizontal member is supported.
- \( h \) is the vertical distance from the horizontal member to the point C.
- \( d_1 \) is the horizontal distance from point A to C.
- \( d_2 \) is the horizontal distance from point C to B.
### Detailed Description of Diagram:
1. **Horizontal Member (AB):**
- Positioned horizontally with a total length \( d_1 + d_2 \).
- Ends labeled A and B.
2. **Vertical Distance (h):**
- Shown as a vertical line from the horizontal member down to C.
3. **Angles (\( \alpha \) and \( \beta \)):**
- \( \alpha \) is the angle between the horizontal member and the left slanted member.
- \( \beta \) is the angle between the horizontal member and the right slanted member.
4. **Vertical Load (W):**
- Shown as a weight hanging from point C downward.
### Equilibrium Conditions:
To solve for the forces, express the equilibrium conditions along the x and y axes, considering the geometry and dimensions provided.
\[
\Sigma F_x =
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