ANSWER THE QUESTION AND DISCUS THE RESULTS. in an oil – water system, the following fluid and sand data are available: h= 75 ft, hp=22.5 ft, po=48.3 lb/ft³, pw=65.76 lb/ft³ , Ho=0.63cp, Bo=1.136, bbl/STB, rw=3 in, re=1000 ft, ko=93.5 md, Distance from the top of the perforations to top of the sand = 30 ft, %3D CALCULATE: THE CRITICAL OIL FLOW RATE USING CHANEY METHOD.

ANSWER THE QUESTION AND DISCUS THE RESULTS. in an oil – water system, the following fluid and sand data are available: h= 75 ft, hp=22.5 ft, po=48.3 lb/ft³, pw=65.76 lb/ft³ , Ho=0.63cp, Bo=1.136, bbl/STB, rw=3 in, re=1000 ft, ko=93.5 md, Distance from the top of the perforations to top of the sand = 30 ft, %3D CALCULATE: THE CRITICAL OIL FLOW RATE USING CHANEY METHOD.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The result of the liquid limit tests where N is the no of blows and w is the water content in % are given as follows: Trial 1 N=11 w=53.9; Trial 2 N=15 w=50.6; Trial 3 N=23 w=48.1; Trial 4 N= 30 w= 46; Trial 5 N= 46 w=43.3; Trial 6 N= 53 w=41. The PL= 30 and the in situ moisture content is 40%. Determine the liquidity index. a.0.56 b.0.59 c.0.91 d.1.25
Just choose the correct answer The total volume of concrete slab (m3) 1.4 2.6.5 3.7 4.8 the total weight of concrete slab(kg) 1.12000 2.9560 3.101164 4.11468 the weight of sand in stock condition 1.2890.867kg 2.3560.435kg 3.2099.898kg 4.2530.751kg The weight of water after adjustment (Kg) 1.638.717 2.938.717 3.738.717 4.838.717
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A soil profile is shown in the figure. If a uniformly distributed load, Δσ, is applied at the ground surface, what is the settlement of the clay layer caused by primary consolidation if the preconsolidation pressure is σc′=200kN/m2 . Use Cs=1/5Cc. CHOICES A. 24 mm B. 56 mm C. 38 mm D. 45 mm
A soil profile is shown in the figure below. A uniformly distributed load, Ao ; is applied at the ground surface equal to 100 kPa. Ao 100 kN/m 2m Yary - 14 kN/m Groundwater table 4 m Yat 18 kN/m Kat 19 kN/m Void ratio, e=0.8 3.5 m L=40 Sand E Clay What is the settlement (in mm) of the clay layer caused by primary consolidation if the clay is normally consolidated? Report your answer to the nearest whole number. O 68 O 190 O 38 O none of the above
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The result of the liquid limit tests where N is the no of blows and w is the water content in % are given as follows: Trial 1 N=11 w=53.9; Trial 2 N=15 w=50.6; Trial 3 N=23 w=48.1; Trial 4 N= 30 w= 46; Trial 5 N= 46 w=43.3; Trial 6 N= 53 w=41. The PL= 20 and the in situ moisture content is 45%. Determine the plasticity index. a.22 b.17 c.27 d.12
Subject Geotechnical engineering : soil mechanics A layer soil shown has the following data H1= 3m. K1= 2x10^-2 cm/sec H2= 4m K2= 3.2x10^-2 cm/sec H3= 6m K3= 4.1 x 10^ -2 cm/sec Compute the equivalent coefficient of permeability in vertical direction. Compute the velocity if h= 4m
The result of the liquid limit tests where N is the no of blows and w is the water content in % are given as follows: Trial 1 N=11 w=53.9; Trial 2 N=15 w=50.6; Trial 3 N=23 w=48.1; Trial 4 N= 30 w= 46; Trial 5 N= 46 w=43.3; Trial 6 N= 53 w=41. The PL=25 and the in situ moisture content is 45%. Determine the liquid limit. O a. 41 O b. 47 O c. 43 O d. 50