and volume increases to 15.3 Liters, what must the new temperature be? 5. A solid sample of KCIO, is put into a test tube, and heated. It will decompose according to the following balanced equation. 2KCIO3 (s) a 2 KCІ +302(8) (s) The oxygen was collected by displacement of water at 22°C, and a total pressure of 802 torr. The volume of gas collected was 0.700 Liters. The vapor pressure of water in the gas phase at 22°C is 21 torr. Questions that require answers are as follows: a. What is the partial pressure of oxygen gas in the container? b. What was the mass of KCIO, that must have 3. been reacted to produce that much oxygen? cof what would 6. Methanol (Methyl Alcohol) is used in race cars. It can be made by reacting Hydrogen gas, and carbon monoxide gas. Suppose 68.5 kg (kilograms) of CO is reacted with 8,60 kg of H, according to the unbalanced equation. H2e) + COe à CH,OH (g) (1)

and volume increases to 15.3 Liters, what must the new temperature be? 5. A solid sample of KCIO, is put into a test tube, and heated. It will decompose according to the following balanced equation. 2KCIO3 (s) a 2 KCІ +302(8) (s) The oxygen was collected by displacement of water at 22°C, and a total pressure of 802 torr. The volume of gas collected was 0.700 Liters. The vapor pressure of water in the gas phase at 22°C is 21 torr. Questions that require answers are as follows: a. What is the partial pressure of oxygen gas in the container? b. What was the mass of KCIO, that must have 3. been reacted to produce that much oxygen? cof what would 6. Methanol (Methyl Alcohol) is used in race cars. It can be made by reacting Hydrogen gas, and carbon monoxide gas. Suppose 68.5 kg (kilograms) of CO is reacted with 8,60 kg of H, according to the unbalanced equation. H2e) + COe à CH,OH (g) (1)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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All changes save 7. When two solutions are mixed, a color change occurs. The data tables show the time between mixing and the color change for two sets of conditions. For Condition One, the solution concentrations were constant and temperature varied. For Condition Two, the temperature was constant and concentrations varied. Condition One: Concentration Time for Temperature (°C) Sample Color to Change 1 10° 36 sec 22° 14 sec Condition Two: Temperature Time for Concentration Sample Color to % Change 1. 100% 15 sec 2. 50% 24 sec Which of these statements is true according to the data? O The reaction rate is greater at 22°C than at 10°C. O Reducing the temperature increases the rate of the reaction. The reaction is affected by changes in temperature not by changes in concentration. O Decreasing the concentration increases the reaction rate. PREVIOUS 17 of 25 NEXT SAVE & EXIT
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I do need help with this problem. It is multiparty. Thank you!
The inital points are ( 0, 27.12) and (0.00250 , 5.17)
Data Analysis: 1. Create an Absorbance (Y) vs. Concentration (X) graph using data from the six standard solutions above. 2. Perform a linear trendline analysis of your six data points. Display the equation and R² value on the graph with a minimum of 8 decimal places. 3. On the same graph, perform a 2nd order polynomial trendline analysis of your six data points. Display the equation and R² value on the graph with a minimum of 8 decimal places. 4. Turn in your graph as the last page of this report. 5. On a separate piece of paper calculate the concentration of the unknown solution using both the linear and 2nd order polynomial trendline equations (Show all work) 6. Choose the best unknown concentration from #4 above and report it with three significant figures in the unknown data table above.
Please create a caption for this table. Solution NaCl Conc. (%) Osmolality (mOsm) % transmittance Absorbance % hemolysis % crenation C distilled 0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72