For the titration of 25.00 mL of 0.1000M HCI with 0,1000 M NaOH, calculate the pH of the reaction mixture after each of the following total volumes of base have been added to the original solution. (Remember to take into account the change in total volume.) (a) 0.00 mL the tolerance is +/-2% SHOW HINT (b) 10.00 mL the tolerance is +/-2% SHOW HINT (c) 24.90 mL

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Chapter1: Chemical Foundations
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**Question 13**

For the titration of 25.00 mL of 0.1000 M HCl with 0.1000 M NaOH, calculate the pH of the reaction mixture after each of the following total volumes of base have been added to the original solution. (Remember to take into account the change in total volume.)

**(a) 0.00 mL**

[Text box for answer]

The tolerance is +/-2%

[Show Hint button]

---

**(b) 10.00 mL**

[Text box for answer]

The tolerance is +/-2%

[Show Hint button]

---

**(c) 24.90 mL**

[Text box for answer]

The tolerance is +/-2%

[Show Hint button]
Transcribed Image Text:**Question 13** For the titration of 25.00 mL of 0.1000 M HCl with 0.1000 M NaOH, calculate the pH of the reaction mixture after each of the following total volumes of base have been added to the original solution. (Remember to take into account the change in total volume.) **(a) 0.00 mL** [Text box for answer] The tolerance is +/-2% [Show Hint button] --- **(b) 10.00 mL** [Text box for answer] The tolerance is +/-2% [Show Hint button] --- **(c) 24.90 mL** [Text box for answer] The tolerance is +/-2% [Show Hint button]
(d) 24.99 mL  
[Input Box]  
The tolerance is +/-2%.

[Show Hint]

(e) 25.00 mL  
[Input Box]  
The tolerance is +/-2%.

[Show Hint]

(f) 25.01 mL  
[Input Box]  
The tolerance is +/-2%.

[Show Hint]

(g) 25.10 mL  
[Input Box]  
The tolerance is +/-2%.

[Show Hint]
Transcribed Image Text:(d) 24.99 mL [Input Box] The tolerance is +/-2%. [Show Hint] (e) 25.00 mL [Input Box] The tolerance is +/-2%. [Show Hint] (f) 25.01 mL [Input Box] The tolerance is +/-2%. [Show Hint] (g) 25.10 mL [Input Box] The tolerance is +/-2%. [Show Hint]
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