An X-ray beam of wavelength 3.4 x 10-10 m makes an angle of 27° with a set of planes in a crystal which results in first order constructive interference. Determine the plane spacing in nanometers. (Please include 2 decimal places).
An X-ray beam of wavelength 3.4 x 10-10 m makes an angle of 27° with a set of planes in a crystal which results in first order constructive interference. Determine the plane spacing in nanometers. (Please include 2 decimal places).
Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter36: Wave Optics
Section: Chapter Questions
Problem 43AP
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Question
![### X-ray Diffraction Exercise
**Problem Statement:**
An X-ray beam of wavelength \( 3.4 \times 10^{-10} \) meters makes an angle of \( 27^\circ \) with a set of planes in a crystal which results in first order constructive interference. Determine the plane spacing in nanometers. (Please include 2 decimal places).
**Solution:**
To solve this problem, you will need to use Bragg's Law which is represented by the equation:
\[ n\lambda = 2d\sin\theta \]
where:
- \( n \) is the order of the interference (for first order, \( n = 1 \))
- \( \lambda \) is the wavelength of the X-ray ( \( 3.4 \times 10^{-10} \) meters)
- \( d \) is the distance between the crystal planes
- \( \theta \) is the angle of incidence ( \( 27^\circ \) )
Rearranging the formula to solve for \( d \):
\[ d = \frac{n\lambda}{2\sin\theta} \]
Step-by-step calculation:
1. Substitute the known values into the equation:
\[ d = \frac{(1)(3.4 \times 10^{-10} \, \text{m})}{2\sin(27^\circ)} \]
2. Calculate \( \sin(27^\circ) \). Use a calculator to find:
\[ \sin(27^\circ) \approx 0.454 \]
3. Substitute this value back into the equation:
\[ d = \frac{3.4 \times 10^{-10}}{2 \times 0.454} \]
4. Perform the division:
\[ d \approx \frac{3.4 \times 10^{-10}}{0.908} \approx 3.74 \times 10^{-10} \, \text{m} \]
5. Convert the result from meters to nanometers. (1 \, \text{m} = 10^9 \, \text{nm}):
\[ d \approx 3.74 \times 10^{-1} \, \text{nm} \]
Thus, the plane spacing \( d \) is approximately \( 0.37 \, \text{nm} \).
**Conclusion:**
The plane spacing is \(](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98ea0ed6-be6f-4556-80a5-46c7ae10c3b9%2Fa95228bb-253e-4fe7-850b-62165ba8d3a8%2Fgrg6dq_processed.png&w=3840&q=75)
Transcribed Image Text:### X-ray Diffraction Exercise
**Problem Statement:**
An X-ray beam of wavelength \( 3.4 \times 10^{-10} \) meters makes an angle of \( 27^\circ \) with a set of planes in a crystal which results in first order constructive interference. Determine the plane spacing in nanometers. (Please include 2 decimal places).
**Solution:**
To solve this problem, you will need to use Bragg's Law which is represented by the equation:
\[ n\lambda = 2d\sin\theta \]
where:
- \( n \) is the order of the interference (for first order, \( n = 1 \))
- \( \lambda \) is the wavelength of the X-ray ( \( 3.4 \times 10^{-10} \) meters)
- \( d \) is the distance between the crystal planes
- \( \theta \) is the angle of incidence ( \( 27^\circ \) )
Rearranging the formula to solve for \( d \):
\[ d = \frac{n\lambda}{2\sin\theta} \]
Step-by-step calculation:
1. Substitute the known values into the equation:
\[ d = \frac{(1)(3.4 \times 10^{-10} \, \text{m})}{2\sin(27^\circ)} \]
2. Calculate \( \sin(27^\circ) \). Use a calculator to find:
\[ \sin(27^\circ) \approx 0.454 \]
3. Substitute this value back into the equation:
\[ d = \frac{3.4 \times 10^{-10}}{2 \times 0.454} \]
4. Perform the division:
\[ d \approx \frac{3.4 \times 10^{-10}}{0.908} \approx 3.74 \times 10^{-10} \, \text{m} \]
5. Convert the result from meters to nanometers. (1 \, \text{m} = 10^9 \, \text{nm}):
\[ d \approx 3.74 \times 10^{-1} \, \text{nm} \]
Thus, the plane spacing \( d \) is approximately \( 0.37 \, \text{nm} \).
**Conclusion:**
The plane spacing is \(
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