Combined interference and diffraction With a green laser λ= (532 ± 0.01)nmDouble slots d =(0.25 ± 0.01)mm with a= (0.080 ± 0.005)mm on a support;Double slots d =(0.50 ± 0.01)mm with a= (0.080 ± 0.005)mm on a support;Optical bench with photosensor connected to Capstone;Ruler;Tape measure. How many bright interference fringes will be observable inside the central diffraction peak of a double slit? In order to answer the question, start with the analysis of single slit diffraction:Calculate the linear position on the screen of the diffraction minimum of order 1 for a slit whose width is a=0.08mm, illuminated by light whose wavelength is λ=532nm(green). Take a distance between the screen and the slot of L=1 meter. Diffraction and Young interference combined:Using your previous result, calculate the number of bright interference fringes present in the central diffraction peak of a double slit whose distance between the two slits is d=0.25mm. The width of the slits (a=0.08mm), the wavelength of the light which illuminates the slits (λ=532nm) and the distance between the screen and the slits (L = 1 meter) remain the same as previously. Redo the calculation by changing d to 0.50 mm.
Combined interference and diffraction
With a green laser λ= (532 ± 0.01)nm
Double slots d =(0.25 ± 0.01)mm with a= (0.080 ± 0.005)mm on a support;
Double slots d =(0.50 ± 0.01)mm with a= (0.080 ± 0.005)mm on a support;
Optical bench with photosensor connected to Capstone;
Ruler;
Tape measure.
How many bright interference fringes will be observable inside the central diffraction peak of a double slit?
In order to answer the question, start with the analysis of single slit diffraction:
Calculate the linear position on the screen of the diffraction minimum of order 1 for a slit whose width is a=0.08mm, illuminated by
Diffraction and Young interference combined:
Using your previous result, calculate the number of bright interference fringes present in the central diffraction peak of a double slit whose distance between the two slits is d=0.25mm. The width of the slits (a=0.08mm), the wavelength of the light which illuminates the slits (λ=532nm) and the distance between the screen and the slits (L = 1 meter) remain the same as previously. Redo the calculation by changing d to 0.50 mm.
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