An object of height 2.9 cm is placed 25 cm in front of a diverging lens of focal length 19 cm. Behind the diverging lens, and 13 cm from it, there is a converging lens of the same focal length. Part (a) Find the location of the final image, in centimeters beyond the converging lens. s"= 14.80 Part (b) X Attempts Remain aheite is strictly forbidden. Doing so What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object. mtotal= = || Grade Su Deductio Potential

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter38: Refraction And Images Formed By Refraction
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An object of height 2.9 cm is placed 25 cm in front of a diverging lens of focal length 19 cm. Behind the diverging lens, and 13 cm from it, there is a converging lens of
the same focal length.
Part (a)
Find the location of the final image, in centimeters beyond the converging lens.
s"= 14.80
Part (b)
X Attempts Remain
aheite is strictly forbidden. Doing so
What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
mtotal= = ||
Grade Su
Deductio
Potential
Transcribed Image Text:An object of height 2.9 cm is placed 25 cm in front of a diverging lens of focal length 19 cm. Behind the diverging lens, and 13 cm from it, there is a converging lens of the same focal length. Part (a) Find the location of the final image, in centimeters beyond the converging lens. s"= 14.80 Part (b) X Attempts Remain aheite is strictly forbidden. Doing so What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object. mtotal= = || Grade Su Deductio Potential
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