A nucleus with 30 protons travels at a velocity of 1.43 x 10^6 m/s through a region of uniform magnetic field strength 3.96 T. The nucleus experiences a magnetic force of 1.01E-11 N. What angle does the nucleus s velocity vector make with respect to the magnetic field direction?Question 1 options: 21.8 degrees 4.4 degrees 19.6 degrees 32.7 degreesQuestion 2 (5 points) A particle with charge 5.32 x 10^-6 C moves at 7.25 x 10^6 m/s through a magnetic field of strength 3.85 T. The angle between the particle s velocity and the magnetic field direction is 38.0 degrees and the particle undergoes an acceleration of 5.4 m/s^2. What is the particle s mass?Question 2 options: 7.0 kg 16.93 kg 1.1 kg 3.2 kgQuestion 3 (5 points) See the attached figure for this problem. A charge of 5.30 x 10^6 C moves to the right as shown through a region containing both a magnetic field of strength 3.91 T directed into the screen and an electric field of strength 2.79 x 10^5 N/C directed downward. The charge continues through the region at a constant velocity (no acceleration). What is the charge s speed?Question 3 options: 5.00E+04 m/s 3.57E+04 m/s 2.14E+04 m/s 7.14E+04 m/sQuestion 4 (5 points) Please refer again to the diagram. This time we have a charge of 8.24 x 10^-6 C moving at velocity 8.86 x 10^5 m/s through a magnetic field of strength 3.42 T and an electric field of strength 6.91 x 10^5 N/C. What is the magnitude of the total force on this charge?Question 4 options: 34.69 N 19.27 N 11.56 N 25.05 NQuestion 5 (5 points) Once more, please refer to the figure. This time the charge is 2.58 x 10^-6 C, the magnetic field strength is 1.35 T and the electric field strength is 5.24 x 10^5 N/C. The charge experiences a total force of magnitude 8.20 N as it enters the region. What is its speed as it enters the region?Question 5 options: 1.97E+06 m/s 1.18E+06 m/s 2.76E+06 m/s 3.35E+06 m/s