A sine wave displayed on an oscilloscope is measured to have a total vertical deflection of 3.5Div and a horizontal distance of 6.9 Div for the waveform. The oscilloscope settings are1V/Div and 5ms/Div. What is the peak to peak voltage of the waveform?A)34.5 VB)3.5 VC)6.9 VD)17.5 V

Option b: This option is correct.To determine the peak to peak voltage of the sine wave, we use Peak…

Answered: A sine wave displayed on an…

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter27: Direct-current Circuits

Section: Chapter Questions

Problem 51CP: The switch in Figure P27.51a closes when Vc23Vand opens when Vc13V. The ideal voltmeter reads a...

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A citizen’s band radio transmitter operates at a frequency of 27.1 MHz. The peak voltage across the transmitter is 10-V. Write an expression for the variation of voltage with time. What is the time for one cycle? use the formula V=Vo sin (2πft)
How was it solved. need g-k Answers: a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 125.0876°h. v(t) = 98.9949sin(20πt + 125.0876°)i. -29.0880 Vj. 0.99959°k. 63.643 ms
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A sine wave displayed on an oscilloscope is measured to have a total vertical deflection of 3.5 Div and a horizontal distance of 6.9 Div for the waveform. The oscilloscope settings are 1V/Div and 5ms/Div. What is the peak to peak voltage of the waveform? A) 34.5 V B) 3.5 V C) 6.9 V D) 17.5 V