Part A An 5.00 kg box sits on a ramp that is inclined at 33.0° above the horizontal. The coefficient of kinetic friction between the box and the surface of the ramp is μk = 0.300. A constant horizontal force F = 24.0 N is applied to the box (Figure 1), and the box moves down the ramp. If the box is initially at rest, what is its speed 2.00 s after the force is applied? Express your answer with the appropriate units. ΜΑ m v = Value S Submit Previous Answers Request Answer × Incorrect; Try Again Provide Feedback ?

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Chapter7: Rotational Motion And The Law Of Gravity
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Part A
An 5.00 kg box sits on a ramp that is inclined at 33.0° above
the horizontal. The coefficient of kinetic friction between the
box and the surface of the ramp is μk = 0.300. A constant
horizontal force F = 24.0 N is applied to the box (Figure 1),
and the box moves down the ramp.
If the box is initially at rest, what is its speed 2.00 s after the force is applied?
Express your answer with the appropriate units.
ΜΑ
m
v =
Value
S
Submit
Previous Answers Request Answer
× Incorrect; Try Again
Provide Feedback
?
Transcribed Image Text:Part A An 5.00 kg box sits on a ramp that is inclined at 33.0° above the horizontal. The coefficient of kinetic friction between the box and the surface of the ramp is μk = 0.300. A constant horizontal force F = 24.0 N is applied to the box (Figure 1), and the box moves down the ramp. If the box is initially at rest, what is its speed 2.00 s after the force is applied? Express your answer with the appropriate units. ΜΑ m v = Value S Submit Previous Answers Request Answer × Incorrect; Try Again Provide Feedback ?
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