An equal tangent vertical curve is to be constructed between grades of -2.0% and +1.0 %. The PVI is at station 11 +000.00 and at elevation 420 m. Due a street crossing the roadway, the elevation of the roadway at station 11 +071.00 must be at 421.5 m. Design the curve. (what is the curve length?)

Q: An incoming grade of +1.800% meets an exiting grade of -2.500% at a PVI having station = 27+32.20…

A: Incoming grade = +1.800% Exiting grade = -2.500% PVI station = 27+32.20 PVI elevation = 231.87…

Q: 1.    Consider a vertical curve with a +3/2% initial grade and -1.1% final grade. The point of…

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Q: answer question 18 only

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Q: An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0%…

A: Solution:GradeG1=-2.0%Grade G2=1.0%Point of vertical intraction elevation=420 mPoint of vertical…

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75%…

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Q: 19. What is the stationing (ft) of the EVC?

A: Length of curve, L = 1100ft  ⇒ 11 stations.   Stationing of BVC = 12+15 ft.

Q: A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and…

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Q: An equal-tangent crest curve connects a +2.0% and a-1.0% grade. The PVC is at station + 670 and the…

A: The curve length will be: Lm=2×100station2 of PVI-station1 of PVCLm=200(1+790-1+670)      =240 ft

Q: An existing roadway has a crest vertical curve with a PVC at station 94+12.00 at elevation 480.00…

A: According to given dataAn existing roadway has a crest vertical curve with a PVC at station 94+12.00…

Q: A curve joins 0% grade with 12.5% grade. The point of intersection is at station 2+282.15 and…

A: PVCSTATION=PVISTA-L2PVCsta=2290.85-1582=2+211.85PVCELV=PVIELV-g1L2PVCelv=68.21+0×6502PVCelv=68.21

Q: have designed a vertical crest curve which joins a +3% E mph and you have determined the curve to be…

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Q: Q2) A proposed highway has two tangents of bearings N 45°54'36" E and N 1°22'30" W. The highway…

A: “Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: NEED ASAP A summit curve has tangents intersects at Pl at station 14+750 with elevation of 76.30m.…

A: PVCSTATION=PVISTA-L2PVCsta=14750-3002=14+600PVCELV=PVIELV-g1L2PVCelv=76.3-0.034×3002PVCelv=71.2

Q: An equal-tangent sag curve of length 920ft needs to be designed for 55 mph to connect an initial…

A: Given:- The length of the sag curve = 920 ft The design speed = 55 mph The initial downgrade = 5%…

Q: A vertical curve is to be design to joint (+3) percent grade with a (-3.5) percent grade, sight…

A: It is required to determine the minimum length of the curve. Assume S < L L=AS21002h1+2h22 Here A…

Q: On a vertical alignment a +10 % grade (back tangent) meets a -4% grade (forward tangent) at station…

A: Initial grade, G1 = 10%Final grade, G2 = -4%Length of the curve, L = 1000 ftElevation of PVC, e =…

Q: 200+00 and elevation 150.00m above the sea level. The centerline of the roadway must clear a pip…

A: According to given data  A vertical curve joins a -0.5% grade to a +1.0% grade. The VPI of the…

Q: highway engineer must stake a symmetrical vertical curve where an entering grade of +0.80% meets an…

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Q: The elevation of PT is at elevation 454.50m while the lowest point on the curve is located 40m from…

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Q: Question 3 An equal-tangent vertical curve is to be constructed between grades of -2 percent and +1…

A: Given :

Q: A vertical road was designed with three tangent lines having a grade of -7.8%, 3.7%, and -2.1%,…

A: G1=-7.8% ,G2=3.7% ,G1'=3.7% ,G2'=-3.2%

Q: A section of a freeway ramp has a +4.0% grade and ends at station 127 + 00 and elevation 138 ft. It…

A: Get the values of Ks and Kc corresponding to the speed of 50 mi/hr from the table of design control…

Q: A vertical curve's PVI has a station of 25+00 and an elevation of 192.36'. The incoming grade is…

A: Draw FBD:

Q: elevation 400 m. Length of first curve is 180 m and that of the second curve is 120 m. What is the…

A: Given data grade, g1 =+4% grade, g2 =-2% elevation =400m Length of first curve = 180 m  Length of…

Q: 3.3 Vertical Alignment 53 ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be…

A: I have tried to solve this problem and also write the given data in diagram plz have gone through it

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

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Q: 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and…

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Q: 600-ft crest vertical curve is to be developed from a +1.80% grade intersecting with a -3.4% grade…

A: Given Initial grade = 1.8% Final grade = -3.4% Station PVI= 15+50= 1550ft Elevation of PVI= 315.76ft…

Q: A horizontal curve on Texas Highway 83 (Tx83) comprises of a two-lane rural highway with a lane…

A: Stopping Sight Distance: It is the minimum sight distance available at any spot having sufficient…

Q: An equal-tangent vertical curve connects a +1.5% initial grade and a -3% final grade. The PVT is at…

A: Following are the given information.Initial grade, Final grade, Station of PVT Elevation of PVT…

Q: 103+51.05 103+53.01 103+47.56 103+49.89

A: 103 + 51.05

Q: A crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The…

A: SPVI = Stationing of PVI = 210+00EPVI = Elevation of PVI = 420.75 ftg1 = Initial grade = 2.5% =…

Q: you have determined the curve to be 1100 ft long. Now, you need to when the BVC is located at…

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Q: Two tangents intersect at V with back tangent having a grade of -2.75% and forward tangent of 6.25%.…

A: PI: PI means Point of Intersection. The point origin where the back and forward tangents intersect…

Q: Problem A highway engineer must stake a symmetrical vertical curve where an entering grade of +0.80%…

A: Given : n1 = +0.80 % n2 = -0.40 % Station - 10 + 100 having an elevation = 140.36 m Allowable grade…

Q: An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75%…

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Q: Questions 5. a) A vertical crest curve has an approach grade +3% and a departure grade -2%. The…

A: Given : Approach grade = +3% and departure grade = -2%  Intersection point level is 100m (AHD)]…

Q: If PVI at sta 5+650 has an elevation of 122.45 m what is the elevation of the grade tangent at…

A: "Since you have asked multiple question, only first question will be solved for you. If you want any…

Q: A horizontal curve on Texas Highway 83 (Tx83) comprises of a two-lane rural highway with a lane…

A: Stopping Sight Distance : It is the minimum sight distance available at any spot having sufficient…

Q: A crest vertical curve joining a + 3 percent and – 4 percent grade is to be designed for 75 mph. If…

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Q: An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI…

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Q: grade of -3.0% is followed by a grade of +2.1% which intersects at station 10+250 and elevation of…

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Drainage of Pavements

Pavement Drainage holds ample significance, as it prevents the accumulation of water or any liquid on the surface of pavements and ensures proper drainage system. With proper design and gradual slopes provided, the water gets easily removed from the surface into the drains, which are essential during heavy rains and unusual weather conditions keeping it less prone to accidents and increasing the durability of the pavement structure.