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3.3 Vertical Alignment 53 ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be constructed between grades of -2.0% (initial) and +1.0% (final). The PVI is at station 110+ 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve.

3.3 Vertical Alignment 53 ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be constructed between grades of -2.0% (initial) and +1.0% (final). The PVI is at station 110+ 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve.

Traffic and Highway Engineering
Traffic and Highway Engineering
5th Edition
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Garber, Nicholas J.
Chapter15: Geometric Design Of Highway Facilities
Section: Chapter Questions
Problem 21P
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Handwritten answers pls. I don’t like the way the textbook solution did it, it’s confusing.
From Eq. 3.3, ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be constructed between grades of -2.0% (initial) and +1.0% (final). The PVI is at station 110+ 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve. The design problem is one of determining the length of the curve required to ensure that station 112+00 is at elevation 424.5 ft. To begin, we use Eq. 3.1: y = ax² +bx+c esc 1 @ New Window New Private Window 14/ b=G₁ = -2.0 #3 A MAR 26 3.3 $ 4 iMessage Vertical Alignment % 5 tv MacBook Pro 6 & 53 7
Transcribed Image Text:From Eq. 3.3, ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be constructed between grades of -2.0% (initial) and +1.0% (final). The PVI is at station 110+ 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve. The design problem is one of determining the length of the curve required to ensure that station 112+00 is at elevation 424.5 ft. To begin, we use Eq. 3.1: y = ax² +bx+c esc 1 @ New Window New Private Window 14/ b=G₁ = -2.0 #3 A MAR 26 3.3 $ 4 iMessage Vertical Alignment % 5 tv MacBook Pro 6 & 53 7
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