Two tangents in profile meet at a vertical point of intersection (VPI). The entrance tangent grade is +5%. The exit tangent grade is -3%. Point on Tangent 1 (POT1) is on the entrance grade. Point on Tangent 2 (POT2) is on the exit grade. An equal tangent vertical curve of 1000.00 ft has been designed to provide a smooth transition between them. Point Station Elevation ft POT1 61+00.00 4900.00 POT 2 242+00.00 4500.00 Elevation of the VPI

Q: An incoming grade of +1.800% meets an exiting grade of -2.500% at a PVI having station = 27+32.20…

A: Incoming grade = +1.800% Exiting grade = -2.500% PVI station = 27+32.20 PVI elevation = 231.87…

Q: An equal-tangent vertical curve is to be constructed between grades of -3% and +2% (travelling left…

A: Given:- Downgrade of curve, g1 = -3% Upgrade of curve, g2 = +2% Station of PVI = 4 + 550.000…

Q: An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75%…

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Q: An equal-tangent sag vertical curve on a section of a highway connects an initial grade of -2% and a…

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Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:-The initial grade of the curve = +1.512%The final grade of the curve = -1.785%The station of…

Q: An equal-tangent sag curve of length 920ft needs to be designed for 55 mph to connect an initial…

A: Given:- The length of the sag curve = 920 ft The design speed = 55 mph The initial downgrade = 5%…

Q: On a vertical alignment a +10 % grade (back tangent) meets a -4% grade (forward tangent) at station…

A: Initial grade, G1 = 10%Final grade, G2 = -4%Length of the curve, L = 1000 ftElevation of PVC, e =…

Q: A crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The…

A: SPVI = Stationing of PVI = 210+00EPVI = Elevation of PVI = 420.75 ftg1 = Initial grade = 2.5% =…

Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Q: A vertical equal-tangent, 100O ft long, connects an initial grade of -2.5% and a final grade of +2%.…

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Q: 1600 ft lomg equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft…

A: Position of tha loest curve x=Lvn12Nhere  Length of sag curve   Lv=1600 ftand   n1=3.5 %  and…

Q: An equal tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed…

A: Grade: G1 = 2% Grade: G2 = -1% Design speed: V = 55 mi/h Station at PVI: = 233+40 Elevation of PV:=…

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.